在函数和返回值类型之前使用( =>
)符号(变量是一个函数时 变量定义时 定义的返回值用=>
表示)
// 完整 类型定义写法
let myAdd: (x: number, y: number) => number =
function(x: number, y: number): number { return x + y; };
// 类型推断,可以省略后面的参数定义
let myAdd: (baseValue: number, increment: number) => number =
function(x, y) { return x + y; }
随便写那个位置,但是写必传参数前是,默认参数 需要传入undefined,写最后使用时可 不传参数
function buildName(firstName = "Will", lastName: string) {
return firstName + " " + lastName;
}
let result4 = buildName(undefined, "Adams");
// okay and returns "Will Adams"
必须写在所有参数后面
function buildName(firstName: string, lastName?: string) {
if (lastName)
return firstName + " " + lastName;
else
return firstName;
}
let result1 = buildName("Bob"); // Bob
let result4 = buildName("Bob", "Adams"); //Bob Adams
...
function buildName(firstName: string, ...restOfName: string[]) {
return firstName + " " + restOfName.join(" ");
}
let employeeName = buildName("Joseph", "Samuel", "Lucas", "MacKinzie");
在函数参数里面定义this的指向,否者为any类型或者编译器设置了–noImplicitThis标记报错
interface Card {
suit: string;
card: number;
}
interface Deck {
suits: string[];
cards: number[];
createCardPicker(this: Deck): () => Card;
}
let deck: Deck = {
suits: ["hearts", "spades", "clubs", "diamonds"],
cards: Array(52),
// NOTE: The function now explicitly specifies that its callee must be of type Deck
createCardPicker: function(this: Deck) {
return () => {
let pickedCard = Math.floor(Math.random() * 52);
let pickedSuit = Math.floor(pickedCard / 13);
return {suit: this.suits[pickedSuit], card: pickedCard % 13};
}
}
}
let cardPicker = deck.createCardPicker();
let pickedCard = cardPicker();
alert("card: " + pickedCard.card + " of " + pickedCard.suit);
当一个函数 传入的参数有多种可能时,可以使用多个函数类型定义,
编译器会按照书写顺序使用重载定义,如果匹配的话就使用,则 一定要把最精确的定义放在最前面。
注意,function pickCard(x): any并不是重载列表的一部分
//下面存在两个重载:一个是接收对象另一个接收数字。 以其它参数调用 pickCard会产生错误。
let suits = ["hearts", "spades", "clubs", "diamonds"];
function pickCard(x: {suit: string; card: number; }[]): number;
function pickCard(x: number): {suit: string; card: number; };
function pickCard(x): any {
// Check to see if we're working with an object/array
// if so, they gave us the deck and we'll pick the card
if (typeof x == "object") {
let pickedCard = Math.floor(Math.random() * x.length);
return pickedCard;
}
// Otherwise just let them pick the card
else if (typeof x == "number") {
let pickedSuit = Math.floor(x / 13);
return { suit: suits[pickedSuit], card: x % 13 };
}
}
let myDeck = [{ suit: "diamonds", card: 2 }, { suit: "spades", card: 10 }, { suit: "hearts", card: 4 }];
let pickedCard1 = myDeck[pickCard(myDeck)];
alert("card: " + pickedCard1.card + " of " + pickedCard1.suit);
let pickedCard2 = pickCard(15);
alert("card: " + pickedCard2.card + " of " + pickedCard2.suit);
参数 少的可以兼容参数多的,多的不能兼容少的
let x = (a: number) => 0;
let y = (b: number, s: string) => 0;
y = x; // OK
x = y; // Error
let x = () => ({name: 'Alice'});
let y = () => ({name: 'Alice', location: 'Seattle'});
x = y; // OK
y = x; // Error, because x() lacks a location property