C语言 定义一个函数,并调用,该函数中完成百文百鸡问题

#include
int main(int argc, char const *argv[])
{
    int num = 0;
    for (int i = 0; i <= 33; i++)
    {
       for (int j = 0; j < 50; j++)
       {
            int x = 100 - i - j;
            if(3*i+2*j+x/3 == 100 && x%3 == 0)
            {
                printf("有%d只,母鸡有%d只,小鸡有%d只\n",i,j,x);
                num++;
            }    
       } 
    }
    printf("共有%d种买法\n",num);
    return 0;
}