王道p18 1.从顺序表中删除具有最小值的元素(假设唯一) 并由函数返回被删元素的值。空出的位置由最后一个元素填补，若顺序表为空，则显示出错信息并退出运行（c语言代码实现）

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 本题代码如下

void deletemin(struct sqlist* s, int* value)
{
	if (s->length == 0)
		printf("表空\n");
	int i = 0;
	int min = s->a[0];
	int k = 0;
	for (i = 1; i < s->length; i++)
	{
		if (s->a[i] < min)
		{
			min = s->a[i];
			k = i;
		}
	}
	*value = min;  
	s->a[k] = s->a[s->length - 1];
	s->length--;
}

完整测试代码

void deletemin(struct sqlist* s, int* value)
{
	if (s->length == 0)
		printf("表空\n");
	int i = 0;
	int min = s->a[0];
	int k = 0;
	for (i = 1; i < s->length; i++)
	{
		if (s->a[i] < min)
		{
			min = s->a[i];
			k = i;
		}
	}
	*value = min;  
	s->a[k] = s->a[s->length - 1];
	s->length--;
}
int main()
{
	struct sqlist s;
	int value;
	int j = 0;
	s.length = 5;
	for (j = 0; j < s.length; j++)
		scanf("%d", &s.a[j]);
	printf("原先顺序表为：");
	for (j = 0; j < s.length; j++)
		printf("%d ", s.a[j]);
	deletemin(&s, &value);
	printf("\n删除后的顺序表为：");
	for (j = 0; j < s.length; j++)
		printf("%d ", s.a[j]);
	printf("\n删除的值为：%d\n", value); 
	return 0;
}