Hive SQL - 50道练习题

目录

  • 建表准备
  • 建表
    • 生成数据
    • 导入数据到hive
  • 需求
  • 1.查询课程编号为“01”的课程比“02”的课程成绩高的所有学生的学号(重点):
  • 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数(重点):
  • 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩(重点):
  • 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩:
  • 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩:
  • 6、查询"李"姓老师的数量:
  • 7、查询学过"张三"老师授课的同学的信息(重点):
  • 8、查询没学过"张三"老师授课的同学的信息(重点):
  • 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息(重点):
  • 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息(重点):
  • 11、查询没有学全所有课程的同学的信息(重点):
  • 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息(重点):
  • 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息(重点):
  • 14、查询没学过"张三"老师讲授的任一门课程的学生姓名(重点):
  • 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩(重点):
  • 16、检索"01"课程分数小于60,按分数降序排列的学生信息(和34类似):
  • 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩(重点):
  • 18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率(重点):
  • 19、按各科成绩进行排序,并显示排名(重点row_number):
  • 20、查询学生的总成绩并进行排名(重点):
  • 21、查询不同老师所教不同课程平均分从高到低显示(重点):
  • 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩(重点):
  • 23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比(重点)
  • 24、查询学生平均成绩及其名次(重点):
  • 25、查询各科成绩前三名的记录(不考虑成绩并列情况)(重点)
  • 26、查询每门课程被选修的学生数:
  • 27、查询出只有两门课程的全部学生的学号和姓名:
  • 28、查询男生、女生人数:
  • 29、查询名字中含有"风"字的学生信息:
  • 30、查询同名同性学生名单,并统计同名人数:
  • 31、查询1990年出生的学生名单(重点year):
  • 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列:
  • 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩:
  • 34、查询课程名称为"数学",且分数低于60的学生姓名和分数:
  • 35、查询所有学生的课程及分数情况(重点):
  • 36、查询任何一门课程成绩在70分以上的学生姓名、课程名称和分数(重点):
  • 37、查询课程不及格的学生:
  • 38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名:
  • 39、求每门课程的学生人数:
  • 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩(重点top):
  • 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩(重点):
  • 42、查询每门课程成绩最好的前三名(重点):
  • 43、统计每门课程的学生选修人数(超过5人的课程才统计):
  • 44、检索至少选修两门课程的学生学号:
  • 45、查询选修了全部课程的学生信息:
  • 46、查询各学生的年龄(周岁):
  • 47、查询本周过生日的学生:
  • 48、查询下周过生日的学生:
  • 49、查询本月过生日的学生:
  • 50、查询12月份过生日的学生:

建表准备

学生表:
Student(s_id,s_name,s_birth,s_sex) #学生编号,学生姓名, 出生年月,学生性别

成绩表:
Score(s_id,c_id,s_s_score) #学生编号,课程编号,分数

课程表:
Course(c_id,c_name,t_id) #课程编号, 课程名称, 教师编号

教师表:
Teacher(t_id,t_name) #教师编号,教师姓名

建表

create table student(s_id string,s_name string,s_birth string,s_sex string) row format delimited fields terminated by '\t';

create table score(s_id string,c_id string,s_score int) row format delimited fields terminated by '\t';

create table course(c_id string,c_name string,t_id string) row format delimited fields terminated by '\t';

create table teacher(t_id string,t_name string) row format delimited fields terminated by '\t';

生成数据

注意路径没有是要创建的,注意行数据是tab键隔开的

vi /opt/module/datas/student.csv

01	赵雷	1990-01-01	男
02	钱电	1990-12-21	男
03	孙风	1990-05-20	男
04	李云	1990-08-06	男
05	周梅	1991-12-01	女
06	吴兰	1992-03-01	女
07	郑竹	1989-07-01	女
08	王菊	1990-01-20	女

vi /opt/module/datas/score.csv

01	01	80
01	02	90
01	03	99
02	01	70
02	02	60
02	03	80
03	01	80
03	02	80
03	03	80
04	01	50
04	02	30
04	03	20
05	01	76
05	02	87
06	01	31
06	03	34
07	02	89
07	03	98

vi /opt/module/datas/course.csv

01	语文	02
02	数学	01
03	英语	03

vi /opt/module/datas/teacher.csv

01	张三
02	李四
03	王五

导入数据到hive

注意也是根据自己的路径不要搞错了

load data local inpath '/opt/module/datas/student.csv' into table student;

load data local inpath '/opt/module/datas/score.csv' into table score;

load data local inpath '/opt/module/datas/course.csv' into table course;
 
load data local inpath '/opt/module/datas/teacher.csv' into table teacher;

ps:hive查询的语法

SELECT [ALL | DISTINCT] select_expr, select_expr, ...
    FROM table_reference
    [WHERE where_condition]
    [GROUP BY col_list [HAVING condition]]
    [CLUSTER BY col_list
      | [DISTRIBUTE BY col_list] [SORT BY| ORDER BY col_list]
    ]
    [LIMIT number]

需求

1.查询课程编号为“01”的课程比“02”的课程成绩高的所有学生的学号(重点):

区别:
法一是from 三个表连接,s_core分为两列,
法二:a和b作为子查询,s_core为一列

方法一:

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
  join score a on student.s_id=a.s_id and a.c_id='01'
  left join score b on student.s_id=b.s_id and b.c_id='02'
where  a.s_score>b.s_score;

方法二:

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on  a.c_id='01'
join score b on  b.c_id='02'
where  a.s_id=student.s_id and b.s_id=student.s_id and a.s_score>b.s_score;

查询结果:
在这里插入图片描述

2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数(重点):

方法一:

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on student.s_id=a.s_id and a.c_id='01'
left join score b on student.s_id=b.s_id and b.c_id='02'
where a.s_score<b.s_score;

方法二:

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on  a.c_id='01'
join score b on  b.c_id='02'
where  a.s_id=student.s_id and b.s_id=student.s_id and a.s_score<b.s_score;

查询结果:
在这里插入图片描述

3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩(重点):

方法一:

select student.s_id,student.s_name,tmp.avgScorse from student
   join (select score.s_id,round(avg(score.s_score),1)as avgScorse
        from score group by s_id)as tmp
  on tmp.avgScorse>=60
where student.s_id = tmp.s_id;

方法二:

select  student.s_id,student.s_name,round(avg (score.s_score),1) as avgScorse from student
join score on student.s_id = score.s_id
group by student.s_id,student.s_name
having avg (score.s_score) >= 60;

在这里插入图片描述

4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩:

(包括有成绩的和无成绩的)

方法一:

select  student.s_id,student.s_name,tmp.avgScore from student
join (
select score.s_id,round(avg(score.s_score),1)as avgScore from score group by s_id)as tmp
on tmp.avgScore < 60
where student.s_id=tmp.s_id
union all
select  s2.s_id,s2.s_name,0 as avgScore from student s2
where s2.s_id not in
    (select distinct sc2.s_id from score sc2);

方法二:

select  score.s_id,student.s_name,round(avg (score.s_score),1) as avgScore from student
inner join score on student.s_id=score.s_id
group by score.s_id,student.s_name
having avg (score.s_score) < 60
union all
select  s2.s_id,s2.s_name,0 as avgScore from student s2
where s2.s_id not in
    (select distinct sc2.s_id from score sc2);

在这里插入图片描述

5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩:

select student.s_id,student.s_name,(count(score.c_id) )as total_count,sum(score.s_score)as total_score
from student
left join score on student.s_id=score.s_id
group by student.s_id,student.s_name ;

Hive SQL - 50道练习题_第1张图片

6、查询"李"姓老师的数量:

select t_name,count(1) from teacher  where t_name like '李%' group by t_name;

在这里插入图片描述

7、查询学过"张三"老师授课的同学的信息(重点):

select student.* from student
join score on student.s_id =score.s_id
join  course on course.c_id=score.c_id
join  teacher on course.t_id=teacher.t_id and t_name='张三';

Hive SQL - 50道练习题_第2张图片

8、查询没学过"张三"老师授课的同学的信息(重点):

select student.* from student
left join (select s_id from score
      join  course on course.c_id=score.c_id
      join  teacher on course.t_id=teacher.t_id and t_name='张三')tmp
on  student.s_id =tmp.s_id
where tmp.s_id is null;

在这里插入图片描述

9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息(重点):

select * from student
join (select s_id from score where c_id =1 )tmp1
    on student.s_id=tmp1.s_id
join (select s_id from score where c_id =2 )tmp2
    on student.s_id=tmp2.s_id;

在这里插入图片描述

10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息(重点):

select student.* from student
join (select s_id from score where c_id =1 )tmp1
    on student.s_id=tmp1.s_id
left join (select s_id from score where c_id =2 )tmp2
    on student.s_id =tmp2.s_id
where tmp2.s_id is null;

在这里插入图片描述

11、查询没有学全所有课程的同学的信息(重点):

–先查询出课程的总数量

   select count(1) from course;

–再查询所需结果

select student.* from student
left join(
      select s_id
        from score
          group by s_id
            having count(c_id)=3)tmp
on student.s_id=tmp.s_id
where tmp.s_id is null;

方法二(一步到位):

select student.* from student
join (select count(c_id)num1 from course)tmp1
left join(
      select s_id,count(c_id)num2
        from score group by s_id)tmp2
on student.s_id=tmp2.s_id and tmp1.num1=tmp2.num2
where tmp2.s_id is null;

在这里插入图片描述

12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息(重点):

select student.* from student
join (select c_id from score where score.s_id=01)tmp1
join (select s_id,c_id from score)tmp2
    on tmp1.c_id =tmp2.c_id and student.s_id =tmp2.s_id
where student.s_id  not in('01')
group by student.s_id,s_name,s_birth,s_sex;

Hive SQL - 50道练习题_第3张图片

13、查询和"01"号的同学学习的课程完全相同的其他同学的信息(重点):

–备注:hive不支持group_concat方法,可用 concat_ws(’|’, collect_set(str)) 实现

select student.*,tmp1.course_id from student
join (select s_id ,concat_ws('|', collect_set(c_id)) course_id from score
      group by s_id having s_id not in (1))tmp1
  on student.s_id = tmp1.s_id
join (select concat_ws('|', collect_set(c_id)) course_id2
            from score  where s_id=1)tmp2
      on tmp1.course_id = tmp2.course_id2;

在这里插入图片描述

14、查询没学过"张三"老师讲授的任一门课程的学生姓名(重点):

select student.* from student
  left join (select s_id from score
          join (select c_id from course join  teacher on course.t_id=teacher.t_id and t_name='张三')tmp2
          on score.c_id=tmp2.c_id )tmp
  on student.s_id = tmp.s_id
  where tmp.s_id is null;

在这里插入图片描述

15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩(重点):

select student.s_id,student.s_name,tmp.avg_score from student
inner join (select s_id from score
      where s_score<60
        group by score.s_id having count(s_id)>1)tmp2
on student.s_id = tmp2.s_id
left join (
    select s_id,round(AVG (score.s_score)) avg_score
      from score group by s_id)tmp
      on tmp.s_id=student.s_id;

在这里插入图片描述

16、检索"01"课程分数小于60,按分数降序排列的学生信息(和34类似):

select student.*,s_score from student,score
where student.s_id=score.s_id and s_score<60 and c_id='01'
order by s_score desc;

在这里插入图片描述

17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩(重点):

select a.s_id,tmp1.s_score as chinese,tmp2.s_score as math,tmp3.s_score as english,
    round(avg (a.s_score),2) as avgScore
from score a
left join (select s_id,s_score  from score s1 where  c_id='01')tmp1 on  tmp1.s_id=a.s_id
left join (select s_id,s_score  from score s2 where  c_id='02')tmp2 on  tmp2.s_id=a.s_id
left join (select s_id,s_score  from score s3 where  c_id='03')tmp3 on  tmp3.s_id=a.s_id
group by a.s_id,tmp1.s_score,tmp2.s_score,tmp3.s_score order by avgScore desc;

Hive SQL - 50道练习题_第4张图片

18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率(重点):

–及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

select course.c_id,course.c_name,tmp.maxScore,tmp.minScore,tmp.avgScore,tmp.passRate,tmp.moderate,tmp.goodRate,tmp.excellentRates from course
join(select c_id,max(s_score) as maxScore,min(s_score)as minScore,
    round(avg(s_score),2) avgScore,
    round(sum(case when s_score>=60 then 1 else 0 end)/count(c_id),2)passRate,
    round(sum(case when s_score>=60 and s_score<70 then 1 else 0 end)/count(c_id),2) moderate,
    round(sum(case when s_score>=70 and s_score<80 then 1 else 0 end)/count(c_id),2) goodRate,
    round(sum(case when s_score>=80 and s_score<90 then 1 else 0 end)/count(c_id),2) excellentRates
from score group by c_id)tmp on tmp.c_id=course.c_id;

在这里插入图片描述

19、按各科成绩进行排序,并显示排名(重点row_number):

-row_number() over()分组排序功能(mysql没有该方法)

select c_id,s_id,s_score,row_number()over(partition by c_id order by s_score desc)as rank from score;

Hive SQL - 50道练习题_第5张图片

20、查询学生的总成绩并进行排名(重点):

select score.s_id,s_name,sum(s_score) sumscore,row_number()over(order by sum(s_score) desc) Ranking
  from score ,student
    where score.s_id=student.s_id
    group by score.s_id,s_name order by sumscore desc;

Hive SQL - 50道练习题_第6张图片

21、查询不同老师所教不同课程平均分从高到低显示(重点):

方法一:

select course.c_id,course.t_id,t_name,round(avg(s_score),2)as avgscore from course
    join teacher on teacher.t_id=course.t_id
    join score on course.c_id=score.c_id
    group by course.c_id,course.t_id,t_name order by avgscore desc;

方法二:

select course.c_id,course.t_id,t_name,round(avg(s_score),2)as avgscore from course,teacher,score
   where teacher.t_id=course.t_id and course.c_id=score.c_id
    group by course.c_id,course.t_id,t_name order by avgscore desc;

在这里插入图片描述

22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩(重点):

select student.*,t1.c_id,t1.s_score,t1.ranking
from(select s_id,c_id,s_score,row_number() over (partition by c_id order by s_score desc) ranking
from score)t1
join student on student.s_id=t1.s_id
where ranking>1 and ranking<4;

Hive SQL - 50道练习题_第7张图片

23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比(重点)

select c.c_id,c.c_name,tmp1.s0_60, tmp1.percentum,tmp2.s60_70, tmp2.percentum,tmp3.s70_85, tmp3.percentum,tmp4.s85_100, tmp4.percentum
from course c
join(select c_id,sum(case when s_score<60 then 1 else 0 end )as s0_60,
               round(100*sum(case when s_score<60 then 1 else 0 end )/count(c_id),2)as percentum
     from score group by c_id)tmp1 on tmp1.c_id =c.c_id
left join(select c_id,sum(case when s_score<70 and s_score>=60 then 1 else 0 end )as s60_70,
               round(100*sum(case when s_score<70 and s_score>=60 then 1 else 0 end )/count(c_id),2)as percentum
     from score group by c_id)tmp2 on tmp2.c_id =c.c_id
left join(select c_id,sum(case when s_score<85 and s_score>=70 then 1 else 0 end )as s70_85,
               round(100*sum(case when s_score<85 and s_score>=70 then 1 else 0 end )/count(c_id),2)as percentum
     from score group by c_id)tmp3 on tmp3.c_id =c.c_id
left join(select c_id,sum(case when s_score>=85 then 1 else 0 end )as s85_100,
               round(100*sum(case when s_score>=85 then 1 else 0 end )/count(c_id),2)as percentum
     from score group by c_id)tmp4 on tmp4.c_id =c.c_id;

在这里插入图片描述

24、查询学生平均成绩及其名次(重点):

select tmp.*,row_number()over(order by tmp.avgScore desc) Ranking from
  (select student.s_id,
          student.s_name,
          round(avg(score.s_score),2) as avgScore
  from student join score
  on student.s_id=score.s_id
  group by student.s_id,student.s_name)tmp
order by avgScore desc;

Hive SQL - 50道练习题_第8张图片

25、查询各科成绩前三名的记录(不考虑成绩并列情况)(重点)

–课程id为01的前三名

select score.c_id,course.c_name,student.s_name,s_score from score
join student on student.s_id=score.s_id
join course on  score.c_id='01' and course.c_id=score.c_id
order by s_score desc limit 3;  

在这里插入图片描述
–课程id为02的前三名

select score.c_id,course.c_name,student.s_name,s_score 
from score
join student on student.s_id=score.s_id
join course on  score.c_id='02' and course.c_id=score.c_id
order by s_score desc limit 3; 

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–课程id为03的前三名

select score.c_id,course.c_name,student.s_name,s_score 
from score
join student on student.s_id=score.s_id
join course on  score.c_id='03' and course.c_id=score.c_id  
order by s_score desc limit 3;

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26、查询每门课程被选修的学生数:

select c.c_id,c.c_name,tmp.number from course c
    join (select c_id,count(1) as number from score
        where score.s_score<60 group by score.c_id)tmp
    on tmp.c_id=c.c_id;

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27、查询出只有两门课程的全部学生的学号和姓名:

select st.s_id,st.s_name from student st
  join (select s_id from score group by s_id having count(c_id) =2)tmp
    on st.s_id=tmp.s_id;

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28、查询男生、女生人数:

select tmp1.man,tmp2.women from
    (select count(1) as man from student where s_sex='男')tmp1,
    (select count(1) as women from student where s_sex='女')tmp2;

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29、查询名字中含有"风"字的学生信息:

select * from student where s_name like '%风%';

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30、查询同名同性学生名单,并统计同名人数:

select s1.s_id,s1.s_name,s1.s_sex,count(*) as sameName
from student s1,student s2
where s1.s_name=s2.s_name and s1.s_id<>s2.s_id and s1.s_sex=s2.s_sex
group by s1.s_id,s1.s_name,s1.s_sex;

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31、查询1990年出生的学生名单(重点year):

select * from student where s_birth like '1990%';

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32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列:

select score.c_id,c_name,round(avg(s_score),2) as avgScore from score
  join course on score.c_id=course.c_id
    group by score.c_id,c_name order by avgScore desc,score.c_id asc;

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33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩:

select score.s_id,s_name,round(avg(s_score),2)as avgScore from score
    join student on student.s_id=score.s_id
    group by score.s_id,s_name having avg(s_score) >= 85;

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34、查询课程名称为"数学",且分数低于60的学生姓名和分数:

select s_name,s_score as mathScore from student
    join (select s_id,s_score
            from score,course
            where score.c_id=course.c_id and c_name='数学')tmp
    on tmp.s_score < 60 and student.s_id=tmp.s_id;

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35、查询所有学生的课程及分数情况(重点):

select a.s_name,
    SUM(case c.c_name when '语文' then b.s_score else 0 end ) as chainese,
    SUM(case c.c_name when '数学' then b.s_score else 0 end ) as math,
    SUM(case c.c_name when '英语' then b.s_score else 0 end ) as english,
    SUM(b.s_score) as sumScore
  from student a
    join score b on a.s_id=b.s_id
    join course c on b.c_id=c.c_id
    group by s_name,a.s_id;

Hive SQL - 50道练习题_第9张图片

36、查询任何一门课程成绩在70分以上的学生姓名、课程名称和分数(重点):

注:不用group by

select student.s_id,s_name,c_name,s_score from student
  join (select sc.* from score sc
        left join(select s_id from score where s_score < 70 group by s_id)tmp
        on sc.s_id=tmp.s_id where tmp.s_id is null)tmp2
    on student.s_id=tmp2.s_id
  join course on tmp2.c_id=course.c_id
order by s_id;

Hive SQL - 50道练习题_第10张图片
– 查询全部及格的信息

select sc.* from score sc
  left join(select s_id from score where s_score < 60 group by s_id)tmp
    on sc.s_id=tmp.s_id
where  tmp.s_id is  null;

– 或(效率低)

select sc.* from score sc
where sc.s_id not in (select s_id from score where s_score < 60 group by s_id);

37、查询课程不及格的学生:

select s_name,c_name as courseName,tmp.s_score
from student
join (select s_id,s_score,c_name
      from score,course
      where score.c_id=course.c_id and s_score < 60)tmp
on student.s_id=tmp.s_id;

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38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名:

select student.s_id,s_name,s_score as score_01
from student
join score on student.s_id=score.s_id
where c_id='01' and s_score >= 80;

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39、求每门课程的学生人数:

select course.c_id,course.c_name,count(1)as selectNum
from course
join score on course.c_id=score.c_id
group by course.c_id,course.c_name;

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40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩(重点top):

select student.*,tmp3.c_name,tmp3.maxScore
from (select s_id,c_name,max(s_score)as maxScore from score
      join (select course.c_id,c_name from course join
                  (select t_id,t_name from teacher where t_name='张三')tmp
            on course.t_id=tmp.t_id)tmp2
      on score.c_id=tmp2.c_id group by score.s_id,c_name
      order by maxScore desc limit 1)tmp3
join student
on student.s_id=tmp3.s_id;

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41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩(重点):

select distinct a.s_id,a.c_id,a.s_score from score a,score b
    where a.c_id <> b.c_id and a.s_score=b.s_score;

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42、查询每门课程成绩最好的前三名(重点):

select tmp1.* from
  (select *,row_number()over(order by s_score desc) ranking
      from score  where c_id ='01')tmp1
where tmp1.ranking <= 3
union all
select tmp2.* from
  (select *,row_number()over(order by s_score desc) ranking
      from score where c_id ='02')tmp2
where tmp2.ranking <= 3
union all
select tmp3.* from
  (select *,row_number()over(order by s_score desc) ranking
      from score where c_id ='03')tmp3
where tmp3.ranking <= 3;

Hive SQL - 50道练习题_第11张图片

43、统计每门课程的学生选修人数(超过5人的课程才统计):

-要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列

select distinct course.c_id,tmp.num from course
    join (select c_id,count(1) as num from score group by c_id)tmp
    where tmp.num>=5 order by tmp.num desc ,course.c_id asc;

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44、检索至少选修两门课程的学生学号:

select s_id,count(c_id) as totalCourse
from score
group by s_id
having count(c_id) >= 2;

Hive SQL - 50道练习题_第12张图片

45、查询选修了全部课程的学生信息:

select student.* 
from student,
     (select s_id,count(c_id) as totalCourse 
      from score group by s_id)tmp
where student.s_id=tmp.s_id and totalCourse=3;

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46、查询各学生的年龄(周岁):

-按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一

方法一:

select s_name,s_birth,
      (year(CURRENT_DATE)-year(s_birth)-
        (case when month(CURRENT_DATE) < month(s_birth) then 1
          when month(CURRENT_DATE) = month(s_birth) and day(CURRENT_DATE) < day(s_birth) then 1
          else 0 end)
        ) as age
    from student;

方法二:

select s_name,s_birth,
  floor((datediff(current_date,s_birth) - floor((year(current_date) - year(s_birth))/4))/365) as age
from student;

Hive SQL - 50道练习题_第13张图片

47、查询本周过生日的学生:

方法一:

select * from student where weekofyear(CURRENT_DATE)+1 =weekofyear(s_birth);

方法二:

select s_name,s_sex,s_birth from student
    where substring(s_birth,6,2)='10'
    and substring(s_birth,9,2)=14;

48、查询下周过生日的学生:

方法一:

select * from student where weekofyear(CURRENT_DATE)+1 =weekofyear(s_birth);

方法二:

select s_name,s_sex,s_birth from student
    where substring(s_birth,6,2)='10'
    and substring(s_birth,9,2)>=15
    and substring(s_birth,9,2)<=21;

49、查询本月过生日的学生:

方法一:

select * from student where MONTH(CURRENT_DATE) =MONTH(s_birth);

方法二:

select s_name,s_sex,s_birth from student where substring(s_birth,6,2)='10';

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50、查询12月份过生日的学生:

select s_name,s_sex,s_birth from student where substring(s_birth,6,2)='12';

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