普通树（双亲表示法存储）转二叉树【左孩子右兄弟表示法】

本文对普通树采用顺序存储结构

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输入格式：

 

 图片来源：

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以下为普通树转二叉树完整代码：

#include
#include

#define MaxSize 50

typedef struct TreeNode
{
    char data;
    struct TreeNode* left_firstchild;
    struct TreeNode* nextsibiling;
}TreeNode,*BinTreeNode;


typedef struct
{
    char data;
    int parent;
}NorTreeNode;

BinTreeNode ConstructTree(NorTreeNode* p,int num)
{
    BinTreeNode Root,cur_node;
    Root = NULL;    // 根节点
    TreeNode* brr[num];     // 指针数组，存放节点
    for(int j=0;jdata = p[j].data;     // 复制data
        cur_node->left_firstchild = cur_node->nextsibiling = NULL;
        brr[j] = cur_node;      // 将节点指针存入数组
        if(Root == NULL) { Root = cur_node; }
    }
    for(int i=0;ileft_firstchild = brr[k];   // 父节点连接孩子节点
                break;
            }
        }
        //   寻找第一个兄弟节点
        for(int k=i+1;knextsibiling = brr[k];  // 连接兄弟节点
                break;
            }
        }

    }


    return Root;
}

void PreorderVisit(BinTreeNode RooT)
{
    if(RooT != NULL)
    {
        printf("%c",RooT->data);
        PreorderVisit(RooT->left_firstchild);
        PreorderVisit(RooT->nextsibiling);
    }

}
int main()
{
    NorTreeNode arr[MaxSize];
    BinTreeNode root;
    int n;
    printf("Number of nodes: \n");
    scanf("%d",&n);
    getchar();  // 接收回车键
    for(int i=0;i

 该代码在Code::Blocks 20.03中测试通过

如有错误，恳请各位批评指正！