本文使用OpenLayers最新版本V5.3.0演示:如何使用OpenLayer完美无偏移加载百度离线瓦片地图。OpenLayers 5.3.0下载地址为:https://github.com/openlayers/openlayers/releases/download/v5.3.0/v5.3.0-dist.zip 。
任意新建空目录命名为geTileMap;解压v5.3.0-dist.zip并复制其中ol.js、ol.css文件至geTileMap目录;geTileMap目录下新建tiles空目录,并复制之前下载的12~18级演示瓦片至tiles目录;最后新建名为index.html文件。
完成上述操作后,目录结构如下:
打开index.html输入如下源码:
Openlayer Tile Map
bd09.js
var MCBAND = [12890594.86, 8362377.87, 5591021, 3481989.83,
1678043.12, 0
];
var LLBAND = [75, 60, 45, 30, 15, 0];
var MC2LL = [
[1.410526172116255e-8, 0.00000898305509648872, -1.9939833816331, 200.9824383106796, -187.2403703815547, 91.6087516669843, -23.38765649603339, 2.57121317296198, -0.03801003308653, 17337981.2],
[-7.435856389565537e-9, 0.000008983055097726239, -0.78625201886289, 96.32687599759846, -1.85204757529826, -59.36935905485877,
47.40033549296737, -16.50741931063887,
2.28786674699375, 10260144.86
],
[-3.030883460898826e-8, 0.00000898305509983578,
0.30071316287616, 59.74293618442277,
7.357984074871, -25.38371002664745,
13.45380521110908, -3.29883767235584,
0.32710905363475, 6856817.37
],
[-1.981981304930552e-8, 0.000008983055099779535,
0.03278182852591, 40.31678527705744,
0.65659298677277, -4.44255534477492,
0.85341911805263, 0.12923347998204, -0.04625736007561, 4482777.06
],
[3.09191371068437e-9, 0.000008983055096812155,
0.00006995724062, 23.10934304144901, -0.00023663490511, -0.6321817810242, -0.00663494467273, 0.03430082397953, -0.00466043876332, 2555164.4
],
[2.890871144776878e-9, 0.000008983055095805407, -3.068298e-8, 7.47137025468032, -0.00000353937994, -0.02145144861037, -0.00001234426596, 0.00010322952773, -0.00000323890364, 826088.5]
];
var LL2MC = [
[-0.0015702102444, 111320.7020616939,
1704480524535203, -10338987376042340,
26112667856603880, -35149669176653700,
26595700718403920, -10725012454188240,
1800819912950474, 82.5
],
[0.0008277824516172526, 111320.7020463578,
647795574.6671607, -4082003173.641316,
10774905663.51142, -15171875531.51559,
12053065338.62167, -5124939663.577472,
913311935.9512032, 67.5
],
[0.00337398766765, 111320.7020202162,
4481351.045890365, -23393751.19931662,
79682215.47186455, -115964993.2797253,
97236711.15602145, -43661946.33752821,
8477230.501135234, 52.5
],
[0.00220636496208, 111320.7020209128,
51751.86112841131, 3796837.749470245,
992013.7397791013, -1221952.21711287,
1340652.697009075, -620943.6990984312,
144416.9293806241, 37.5
],
[-0.0003441963504368392, 111320.7020576856,
278.2353980772752, 2485758.690035394,
6070.750963243378, 54821.18345352118,
9540.606633304236, -2710.55326746645,
1405.483844121726, 22.5
],
[-0.0003218135878613132, 111320.7020701615,
0.00369383431289, 823725.6402795718,
0.46104986909093, 2351.343141331292,
1.58060784298199, 8.77738589078284,
0.37238884252424, 7.45
]
];
function lngLatToMercator(T) {
var c = new cd(T[0], T[1]);
var r = convertLL2MC(c);
return [r.lng, r.lat];
}
function mercatorToLngLat(T) {
var c = new cd(T[0], T[1]);
var r = convertMC2LL(c);
return [r.lng, r.lat];
}
function convertLL2MC(T) {
var cL, cN;
T.lng = getLoop(T.lng, -180, 180);
T.lat = getRange(T.lat, -74, 74);
cL = new cd(T.lng, T.lat);
for(var cM = 0; cM < LLBAND.length; cM++) {
if(cL.lat >= LLBAND[cM]) {
cN = LL2MC[cM];
break
}
}
if(!cN) {
for(var cM = LLBAND.length - 1; cM >= 0; cM--) {
if(cL.lat <= -LLBAND[cM]) {
cN = LL2MC[cM];
break
}
}
}
var cO = convertor(T, cN);
var T = new cd(cO.lng.toFixed(2), cO.lat.toFixed(2));
return T
}
function convertMC2LL(cL) {
var cM, cO;
cM = new cd(Math.abs(cL.lng), Math.abs(cL.lat));
for(var cN = 0; cN < MCBAND.length; cN++) {
if(cM.lat >= MCBAND[cN]) {
cO = MC2LL[cN];
break
}
}
var T = convertor(cL, cO);
var cL = new cd(T.lng.toFixed(6), T.lat.toFixed(6));
return cL
}
function getRange(cM, cL, T) {
if(cL != null) {
cM = Math.max(cM, cL)
}
if(T != null) {
cM = Math.min(cM, T)
}
return cM
}
function getLoop(cM, cL, T) {
while(cM > T) {
cM -= T - cL
}
while(cM < cL) {
cM += T - cL
}
return cM
}
function convertor(cM, cN) {
if(!cM || !cN) {
return
}
var T = cN[0] + cN[1] * Math.abs(cM.lng);
var cL = Math.abs(cM.lat) / cN[9];
var cO = cN[2] + cN[3] * cL + cN[4] * cL * cL + cN[5] * cL *
cL * cL + cN[6] * cL * cL * cL * cL + cN[7] * cL *
cL * cL * cL * cL + cN[8] * cL * cL * cL * cL *
cL * cL;
T *= (cM.lng < 0 ? -1 : 1);
cO *= (cM.lat < 0 ? -1 : 1);
return new cd(T, cO)
}
function cd(T, cL) {
if(isNaN(T)) {
T = bV(T);
T = isNaN(T) ? 0 : T
}
if(b3(T)) {
T = parseFloat(T)
}
if(isNaN(cL)) {
cL = bV(cL);
cL = isNaN(cL) ? 0 : cL
}
if(b3(cL)) {
cL = parseFloat(cL)
}
this.lng = T;
this.lat = cL
}
cd.isInRange = function(T) {
return T && T.lng <= 180 && T.lng >= -180 && T.lat <= 74 &&
T.lat >= -74
};
cd.prototype.equals = function(T) {
return T && lat == T.lat && lng == T.lng
};
function bV(cN) {
var cL = "";
var cU, cS, cQ = "";
var cT, cR, cP, cO = "";
var cM = 0;
var T = /[^A-Za-z0-9\+\/\=]/g;
if(!cN || T.exec(cN)) {
return cN
}
cN = cN.replace(/[^A-Za-z0-9\+\/\=]/g, "");
do {
cT = cf.indexOf(cN.charAt(cM++));
cR = cf.indexOf(cN.charAt(cM++));
cP = cf.indexOf(cN.charAt(cM++));
cO = cf.indexOf(cN.charAt(cM++));
cU = (cT << 2) | (cR >> 4);
cS = ((cR & 15) << 4) | (cP >> 2);
cQ = ((cP & 3) << 6) | cO;
cL = cL + String.fromCharCode(cU);
if(cP != 64) {
cL = cL + String.fromCharCode(cS)
}
if(cO != 64) {
cL = cL + String.fromCharCode(cQ)
}
cU = cS = cQ = "";
cT = cR = cP = cO = ""
} while (cM < cN.length);
return cL
}
function b3(T) {
return typeof T == "string"
}
保存后浏览器中运行演示OpenLayer完美无偏移加载百度离线瓦片地图效果。下图为Chrome中运行实例截图和局部放大后截图:
如需要定位的话,添加以下方法:
function searchPoint(_point) {
_point = tobdMap(_point.split(","));//如果传入的是火星坐标系的话,要转成百度坐标系
var point = new ol.Feature({geometry:
new ol.geom.Point(ol.proj.fromLonLat(_point, 'BD:09'))})// 将经纬度转成BD:09投影,此投影需引入bd09.js
point.setStyle(new ol.style.Style({
image:new ol.style.Icon({
anchor: [0.5, 1],
src:
basePath + "/img/localpoint.png"
})
}));
pointSource.clear();
pointSource.addFeature(point);
map.setView(new ol.View({
center:ol.proj.transform(_point, 'EPSG:4326', 'EPSG:3857'),
zoom:8,
maxZoom:19
}));
};
//火星坐标系转百度坐标系
function tobdMap(coordinate) {
let x_pi = 3.14159265358979324 * 3000.0 / 180.0;
let x = coordinate[0];
let y = coordinate[1];
let z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);
let theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);
let lngs = z * Math.cos(theta) + 0.0065;
let lats = z * Math.sin(theta) + 0.006;
let zb=[];
zb[0]=lngs;
zb[1]=lats;
return zb;
}