C++继承同名静态成员处理方式

#include 
#include 
using namespace std;

class Base
{
public:
	static void func()
	{
		cout << "Base-static void func()" << endl;
	}
	static void func(int a)
	{
		cout << "Base-static void func(int a)" << endl;
	}
	static int m_A;
};

int Base::m_A = 100;

class Son :public Base
{
public:
	static void func()
	{
		cout << "Son-static void func()" << endl;
	}
	static int m_A;
};
int Son::m_A = 200;
//同名成员属性
void test01()
{
	cout << "通过对象访问" << endl;
	Son s;
	cout << s.m_A << endl;
	cout << s.Base::m_A << endl;
	cout << "通过类名访问" << endl;
	cout << Son::m_A << endl;
	cout << Son::Base::m_A << endl;
}

//同名成员函数
void test02()
{
	cout << "通过对象访问" << endl;
	Son s;
	s.func();
	s.Base::func();

	cout << "通过类名访问" << endl;
	Son::func();
	Son::Base::func();
	//出现同名，子类会隐藏掉父类中所有同名成员函数，需要加作用域访问
	Son::Base::func(100);
}

int main()
{
	test01();
	test02();
	return 0;
}