实验7，，= =

最近开始学习汇编咯～，，下面是王爽的《汇编语言（第二版）》中实验7的解决方案

PS：这本书大赞啊，，，很通俗易懂

assume cs:codesg,ss:stacksg



data segment

    db '1975','1976','1977','1978','1979','1980','1981','1982','1983'



    db '1984','1985','1986','1987','1988','1989','1990','1991','1992'



    db '1993','1994','1995'



    dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514



    dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000



    dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226



    dw 11452,14430,15257,17800





data ends



table segment

	db 21 dup ('year summ ne ?? ')

table ends



stacksg segment

	db 8 dup(0)

stacksg ends



codesg segment

start:	mov ax,data

	mov ds,ax

	mov ax,table

	mov es,ax

	mov ax,stacksg

	mov ss,ax

	mov sp,8



	mov cx,21

	mov bx,0

	mov bp,0



s1:	push cx

	

	;copy year

	mov cx,4

	mov si,0

s2:	mov al,[bx+si]

	mov es:[bp+si],al

	inc si

	loop s2



	;copy summ

	mov cx,4

	mov si,0

s3:	mov al,[bx+si+84]

	mov es:[bp+si+5],al

	inc si

	loop s3

	

	;copy ne

	mov cx,2

	mov si,0

s4:	mov al,[bx+si+168]

	mov es:[bp+si+10],al

	inc si

	loop s4



	

	add bx,4

	add bp,16	

	pop cx

	loop s1



	mov ax,4c00h

	int 21h

codesg ends



end start