LeetCode Set Matrix Zeroes

class Solution {

public:

    void setZeroes(vector<vector<int> > &matrix) {

        int rows = matrix.size();

        int cols = matrix[0].size();

        

        bool col_has_zero = false;

        bool row_has_zero = false;

        

        for (int i=0; i<cols; i++) {

            if (matrix[0][i] == 0) { 

                row_has_zero = true;

                break;

            }

        }

        

        for (int i=0; i<rows; i++) {

            if (matrix[i][0] == 0) {

                col_has_zero = true;

                break;

            }

        }

        

        for (int i=1; i<rows; i++) {

            for (int j=1; j<cols; j++) {

                if (matrix[i][j] != 0) continue;

                matrix[i][0] = 0;

                matrix[0][j] = 0;

            }

        }

        

        for (int i=1; i<rows; i++) {

            for (int j=1; j<cols; j++) {

                if (!matrix[i][0] || !matrix[0][j]) {

                    matrix[i][j] = 0;

                }

            }

        }



        for (int i=0; row_has_zero && i<cols; i++) matrix[0][i] = 0;

        for (int i=0; col_has_zero && i<rows; i++) matrix[i][0] = 0;



    }

};

没意思，搞个几个bit的额外空间会死么

第二轮：

Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.

click to show follow up.

Follow up:

Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?

class Solution {

public:

    void setZeroes(vector<vector<int> > &matrix) {

        bool first_row_zero = false;

        bool first_col_zero = false;

        

        int rows = matrix.size();

        if (rows < 1) {

            return;

        }

        int cols = matrix[0].size();

        if (cols < 1) {

            return;

        }

        

        for (int i=0; i<cols; i++) {

            if (matrix[0][i] == 0) {

                first_row_zero = true;

                break;

            }

        }

        

        for (int i=0; i<rows; i++) {

            if (matrix[i][0] == 0) {

                first_col_zero = true;

                break;

            }

        }

        

        for (int i=1; i<rows; i++) {

            for (int j=1; j<cols; j++) {

                if (matrix[i][j] == 0) {

                    matrix[0][j] = 0;

                    matrix[i][0] = 0;

                }

            }

        }

        

        for (int i=1; i<rows; i++) {

            if (matrix[i][0] == 0) {

                for (int j=1; j<cols; j++) matrix[i][j] = 0;

            }

        }

        

        

        for (int i=1; i<cols; i++) {

            if (matrix[0][i] == 0) {

                for (int j=1; j<rows; j++) matrix[j][i] = 0;

            }

        }

        

        for (int i=0; i<cols && first_row_zero; i++) matrix[0][i] = 0;

        for (int i=0; i<rows && first_col_zero; i++) matrix[i][0] = 0;

    }

};

 

没有一次AC，最后做填充的时候应该出去最左边的列和最上面的行