75. Sort Colors
Given an array with n objects colored red, white or blue, sort them **in-place **so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Example:
Input: [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
三色排序问题。使用 in-palce
方式解决,就是 比较-替换
。
解:
从头开始遍历, lt = 0,i = 0, rt = length -1,,如果i为0,与 lt 交换,i++, lt++;;如果是1,i++;如果是2 与 rt 交换,rt --。
以下为代码:
int lt = 0, i = 0, rt = nums.length - 1;
while (i <= rt) {
if (nums[i] == 0) {
int tmp = nums[i];
nums[i] = nums[lt];
nums[lt] = tmp;
i++;
lt++;
} else if (nums[i] == 1)
i++;
else if (nums[i] == 2) {
int tmp = nums[i];
nums[i] = nums[rt];
nums[rt] = tmp;
rt--;
}
}