求最小差值的数字

输入一些数字，求哪些对数字差值最小：

#include 
#define max 10

int main()
{
    int arr[max] = { 0 };
    for (int i = 0; i < max; i++)//可以无序输入
    {
        scanf("%d", &arr[i]);
    }
    for (int i = 0; i < max - 1; i++)//先排序，这里是冒泡排序
    {
        for (int j = 0; j < max - 1 - i; j++)
        {
            if (arr[j] > arr[j + 1])
            {
                int temp = arr[j];
                arr[j] = arr[j + 1];
                arr[j + 1] = temp;
            }
        }
    }
    int min_diff = arr[1] - arr[0];
    int ans[max * 2 - 2] = { 0 };
    int count = 0;
    for (int i = 1; i < max; i++)//求最小差值，不断更新最小差值
    {
        int diff = arr[i] - arr[i - 1];
        if (diff < min_diff)//出现更小差值时，ans数组全部更新
        {
            min_diff = diff;
            count = 0;
            ans[count++] = arr[i - 1];
            ans[count++] = arr[i];
        }
        else if (diff == min_diff)//出现差值相等的一对数值
        {
            ans[count++] = arr[i - 1];
            ans[count++] = arr[i];
        }
    }
    for (int i = 0; i < count; i++)//打印
    {
        printf("%d ", ans[i]);
        if ((i + 1) % 2 == 0)//每对一行
        {
            printf("\n");
        }
    }

    return 0;
}