Linux中根据访问日志统计访问量最高的前N个IP

   前段时间面试中被问到如上问题，日常不怎么注意积累，以此谨记。

访问IP    页面
[nxuser@im440-zh test]$ vi log 135.252.172.181  page1

136.252.172.182  page1

135.252.172.181  page2

135.252.172.183  page1

136.252.172.184  page1

135.252.172.181  page3

135.252.172.185  page1

136.252.172.182  page2

135.252.172.183  page2

135.252.172.181  page4

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

136.252.172.182  page1

代码实现：
1 [nxuser@im440-zh test]$ awk '{print $1}' log|sort |uniq -c|sort -r -n -k 1|head -n 3

 结果：

1      15 136.252.172.182

2       4 135.252.172.181

3       2 135.252.172.183

   注意 第二sort 中 -n ,否则出现如下结果：

1       4 135.252.172.181

2       2 135.252.172.183

3      15 136.252.172.182