hdu 2066(最短路bellmanFord)

/*

  Name: 最短路(bellmanFord) 

  Copyright: 

  Author: Try_86

  Date: 12/04/12 12:42

  Description: 对每个起始点运行一次bellmanFord,求最短路 

*/



#include <cstdio>

#include <iostream>



using namespace std;



const int N = 1005;

const int M = 500500;

const int MAX = 1000000000;



int dis[N], ss[N], ds[N];

struct edge {



    int u;

    int v;

    int w;

}e[M];



void init(int vs, int s) {

    for (int i=1; i<=vs; ++i) dis[i] = MAX;

    dis[s] = 0;

    return ;

} 



void relax(int u, int v, int w) {

    if (dis[v] > dis[u] + w) dis[v] = dis[u] + w;

    return ;

}



void bellmanFord(int es, int vs, int s) {

    init(vs, s);

    for (int i=1; i<vs; ++i) {

        for (int j=0; j<es; ++j) relax(e[j].u, e[j].v, e[j].w);

    }

    return ;

}



int main() {

    int t, s, d;

    while (scanf("%d%d%d", &t, &s, &d) != EOF) {

        int vs = 0;

        for (int i=0; i<t; ++i) {

            scanf ("%d%d%d", &e[i].u, &e[i].v, &e[i].w);

            e[i+t].v = e[i].u;

            e[i+t].u = e[i].v;

            e[i+t].w = e[i].w;

            if (vs < e[i].u) vs = e[i].u;

            if (vs < e[i].v) vs = e[i].v;

        }

        for (int i=0; i<s; ++i) scanf ("%d", &ss[i]);

        for (int i=0; i<d; ++i) scanf ("%d", &ds[i]);

        int mins = MAX;

        for (int i=0; i<s; ++i) {

            bellmanFord(t<<1, vs, ss[i]);

            for (int j=0; j<d; ++j) {

                if (mins > dis[ds[j]]) mins = dis[ds[j]];

            }

        }

        printf ("%d\n", mins);

    }

    return 0;

}

 

你可能感兴趣的:(for)