JUC全家桶 | Java多线程八锁问题

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问题1

问:如下代码,两个方法谁先输出?

答:先输出 call,后 sendMsg

原因:被 synchronized 修饰的方法,锁的对象是方法调用者,所以说这里两个方法调用的对象是同一个,先调用的先执行!

public class Lock1 {

    public static void main(String[] args) throws InterruptedException {
        Phone phone = new Phone();

        new Thread(phone::call, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(phone::sendMsg, "B").start();
    }

}

class Phone {

    synchronized void call() {
        System.out.println("call");
    }

    synchronized void sendMsg() {
        System.out.println("sendMsg");
    }

}

问题2

问:如下代码,两个方法谁先输出?

答:先输出 call,后 sendMsg

原因:被 synchronized 修饰的方法,锁的对象是方法调用者,所以说这里两个方法调用的对象是同一个,先调用的先执行!

public class Lock2 {

    public static void main(String[] args) throws InterruptedException {
        Phone phone = new Phone();

        new Thread(phone::call, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(phone::sendMsg, "B").start();
    }

}

class Phone {

    synchronized void call() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("call");
    }

    synchronized void sendMsg() {
        System.out.println("sendMsg");
    }

}

问题3

问:如下代码,两个方法谁先输出?

答:先输出 sendMsg,后 call

原因:没有加锁的方法不受锁的影响,所以按照休眠时间 sendMsg 会先输出

public class Lock3 {

    public static void main(String[] args) throws InterruptedException {
        Phone phone = new Phone();

        new Thread(phone::call, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(phone::sendMsg, "B").start();
    }

}

class Phone {

    synchronized void call() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("call");
    }

    void sendMsg() {
        System.out.println("sendMsg");
    }

}

问题4

问:如下代码,两个方法谁先输出?

答:先输出 sendMsg,后 call

原因:被 synchronized 修饰的方法,锁的对象是方法调用者。这里锁的是两个不同的调用者,所以互不影响,按照休眠时间 sendMsg 会先输出

public class Lock4 {

    public static void main(String[] args) throws InterruptedException {
        Phone phoneA = new Phone();
        Phone phoneB = new Phone();

        new Thread(phoneA::call, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(phoneB::sendMsg, "B").start();
    }

}

class Phone {

    synchronized void call() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("call");
    }

    synchronized void sendMsg() {
        System.out.println("sendMsg");
    }

}

问题5

问:如下代码,两个方法谁先输出?

答:先输出 sendMsg,后 call

原因:被 synchronized 修饰的方法,锁的对象是方法调用者。这里锁的是两个不同的调用者,所以互不影响,按照休眠时间 sendMsg 会先输出

public class Lock5 {

    public static void main(String[] args) throws InterruptedException {
        Phone phoneA = new Phone();
        Phone phoneB = new Phone();

        new Thread(phoneA::call, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(phoneB::sendMsg, "B").start();
    }

}

class Phone {

    synchronized void call() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("call");
    }

    synchronized void sendMsg() {
        System.out.println("sendMsg");
    }

}

问题6

问:如下代码,两个方法谁先输出?

答:先输出 call,后 sendMsg

原因:被 synchronized 修饰的方法,锁的对象是方法调用者。这里两个方法都是静态方法,锁的是同一对象(Phone.class),所以先调用的先执行

public class Lock6 {

    public static void main(String[] args) throws InterruptedException {
        Phone phoneA = new Phone();
        Phone phoneB = new Phone();

        new Thread(() -> {
            phoneA.call();
        }, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(() -> {
            phoneB.sendMsg();
        }, "B").start();
    }

}

class Phone {

    static synchronized void call() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("call");
    }

    static synchronized void sendMsg() {
        System.out.println("sendMsg");
    }

}

问题7

问:如下代码,两个方法谁先输出?

答:先输出 sendMsg,后 call

原因:被 synchronized 修饰的方法,锁的对象是方法调用者。这里一个是静态方法,一个是非静态方法,锁的对象不同(A线程锁的对象是 Phone.class,B线程锁的对象是 phone 对象),按照休眠时间 sendMsg 会先输出

public class Lock7 {

    public static void main(String[] args) throws InterruptedException {
        Phone phone = new Phone();

        new Thread(() -> {
            phone.call();
        }, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(() -> {
            phone.sendMsg();
        }, "B").start();
    }

}

class Phone {

    static synchronized void call() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("call");
    }

    synchronized void sendMsg() {
        System.out.println("sendMsg");
    }

}

问题8

问:如下代码,两个方法谁先输出?

答:先输出 sendMsg,后 call

原因:被 synchronized 修饰的方法,锁的对象是方法调用者。这里一个是静态方法,一个是非静态方法,锁的对象不同(A线程锁的对象是 Phone.class,B线程锁的对象是 phoneB 对象),按照休眠时间 sendMsg 会先输出

public class Lock8 {

    public static void main(String[] args) throws InterruptedException {
        Phone phoneA = new Phone();
        Phone phoneB = new Phone();

        new Thread(() -> {
            phoneA.call();
        }, "A").start();

        TimeUnit.SECONDS.sleep(1);

        new Thread(() -> {
            phoneB.sendMsg();
        }, "B").start();
    }

}

class Phone {

    static synchronized void call() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("call");
    }

    synchronized void sendMsg() {
        System.out.println("sendMsg");
    }

}

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