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67. 二进制求和 力扣76题—python

输入: a = “11”, b = “1”
输出: “100”

def jinzhi(a,b):
sum = int(a,2)+int(b,2) # 二进制转化为十进制再求和
print(sum) # 打印求和的结构(十进制的)
sum = str(sum) # 将其转化为字符串
return bin(int(sum,10)) # 将其返回二进制
a = ‘1010’
b = ‘1011’
print(jinzhi(a,b)[2:])

“10101”