编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 s
的形式给出。
不要给另外的数组分配额外的空间,你必须**原地修改输入数组**、使用 O(1) 的额外空间解决这一问题。
示例 1:
输入:s = ["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:s = ["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
直接用双指针就完事了
class Solution {
public:
void reverseString(vector<char>& s) {
int behind = s.size()-1;
int front = 0;
char temp;
while(front <= behind)
{
temp = s[front];
s[front] = s[behind];
s[behind] = temp;
front++;
behind--;
}
}
};