LeetCode344. 反转字符串

344. 反转字符串

编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间,你必须**原地修改输入数组**、使用 O(1) 的额外空间解决这一问题。

示例 1:

输入:s = ["h","e","l","l","o"]
输出:["o","l","l","e","h"]

示例 2:

输入:s = ["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]

代码

直接用双指针就完事了

class Solution {
public:
    void reverseString(vector<char>& s) {
        int behind = s.size()-1;
        int front = 0;
        char temp;
        while(front <= behind)
        {
            temp = s[front];
            s[front] = s[behind];
            s[behind] = temp;
            front++;
            behind--;
        }
    }
};

LeetCode344. 反转字符串_第1张图片

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