LeetCode腾讯精选50题---344,557

Day17

344. 反转字符串 (Easy)

344. 反转字符串 (Easy)

"""
    编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
    不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
    你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

    示例 1：
    输入：["h","e","l","l","o"]
    输出：["o","l","l","e","h"]

    示例 2：
    输入：["H","a","n","n","a","h"]
    输出：["h","a","n","n","a","H"]
"""
from typing import List


class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        :type s: List[str]
        :rtype: None Do not return anything, modify s in-place instead.
        """
        s.reverse()

557. 反转字符串中的单词 III (Easy)

557. 反转字符串中的单词 III (Easy)

"""
    给定一个字符串，你需要反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初始顺序。

    示例：
    输入："Let's take LeetCode contest"
    输出："s'teL ekat edoCteeL tsetnoc"
"""


class Solution:
    def reverseWords(self, s: str) -> str:
        """
        :type s: str
        :rtype: str
        """
        return ' '.join(s.split(' ')[::-1])[::-1]