【C语言】五字棋/三子棋代码（含任意多子）
五子棋代码c语言简单实现
（pvc版和pvp版都有）
人与电脑下，人与人下都实现了
案例演示：
三子棋
案例演示：
五子棋
代码展示：
#define _CRT_SECURE_NO_WARNINGS 1
#define X 10 //行
#define Y 15 //列
#define NUM 5//几子赢
//三子棋： X=3 Y=3 NUM=3
//五子棋： X>=10 Y>=10 NUM=5
//多子棋：（N子棋）NUM=N
#include
#include
#include
void menu();
void startgame();
void gamePvC();
void gamePvP();
void initboard(char board[X][Y]);
void printboard(char board[X][Y]);
void playermove1(char board[X][Y]);
void playermove2(char board[X][Y]);
void PCmove(char board[X][Y]);
char iswin(char board[X][Y], int x, int y);
int Full(char board[X][Y]);
char flag = 'a';
int main()
{
startgame();
//将游戏完全封装起来
//实现一个函数对应一个功能
return 0;
}
//菜单栏
void menu()
{
printf(" ------------------------\n");
printf("| 0.退出游戏 |\n");
printf("| 1.PvC人机对局 |\n");
printf("| 2.PvP双人对局 |\n");
printf(" ------------------------\n");
}
//游戏开始
void startgame()
{
int ret = 0;
do
{
menu();
scanf("%d", &ret);
switch (ret)
{
case 0:
printf("game over\n");
break;
case 1:
gamePvC();
break;
case 2:
gamePvP();
break;
default:
printf("输入错误，请重新输入！\n");
break;
}
} while (ret);
}
//人机对局游戏
void gamePvC()
{
char board[X][Y] = { '\0' };
initboard(board);
printboard(board);
while (1)
{
playermove1(board);
if (flag == '*') break;
if (Full(board) == 1) { flag = '='; break; }
PCmove(board);
if (flag == '#') break;
if (Full(board) == 1) { flag = '='; break; }
}
if (flag == '*') printf("玩家胜利\n");
if (flag == '#') printf("电脑胜利\n");
if (flag == '=') printf("平局\n");
}
//双人对局游戏
void gamePvP()
{
char board[X][Y] = { '\0' };
initboard(board);
printboard(board);
while (1)
{
playermove1(board);
if (flag == '*') break;
if (Full(board) == 1) { flag = '='; break; }
playermove2(board);
if (flag == '@') break;
if (Full(board) == 1) { flag = '='; break; }
}
if (flag == '*') printf("玩家1胜利\n");
if (flag == '@') printf("玩家2胜利\n");
if (flag == '=') printf("平局\n");
}
//遍历棋盘
void initboard(char board[X][Y])
{
for (int i = 0; i < X; i++)
{
for (int j = 0; j < Y; j++)
{
board[i][j] = ' ';
}
}
}
//打印棋盘
void printboard(char board[X][Y])
{
for (int i = 0; i < X; i++)
{
if (i == 0)
{
printf(" ");
for (int k = 1; k <= Y; k++)
{
printf("%2d列", k);
if (k == Y)printf("\n ");
}
for (int k = 0; k < Y; k++)
{
printf("+---");
if (k == Y - 1)printf("+\n");
}
}
for (int j = 0; j < Y; j++)
{
if (j == 0) printf("%2d行", i + 1);
printf("|");
printf(" %c ", board[i][j]);
if (j == Y - 1)printf("|\n ");
}
for (int k = 0; k < Y; k++)
{
printf("+---");
if (k == Y - 1)printf("+\n");
}
}
}
//玩家1下棋 *
void playermove1(char board[X][Y])
{
while (1)
{
int x = 0, y = 0;
printf("玩家1，（*玩家）请输入行数和列数以此下棋\n");
scanf("%d %d", &x, &y);
if (x <= X && x >= 1 && y <= Y && y >= 1 && (board[x - 1][y - 1] == ' '))
{
board[x - 1][y - 1] = '*';
flag = iswin(board, x, y);
break;
}
else
{
printf("输入错误，请重新输入\n");
}
}
}
//玩家2下棋 @
void playermove2(char board[X][Y])
{
while (1)
{
int x = 0, y = 0;
printf("玩家2，（@玩家）请输入行数和列数以此下棋\n");
scanf("%d %d", &x, &y);
if (x <= X && x >= 1 && y <= Y && y >= 1 && (board[x - 1][y - 1] == ' '))
{
board[x - 1][y - 1] = '@';
flag = iswin(board, x, y);
break;
}
else
{
printf("输入错误，请重新输入\n");
}
}
}
//电脑下棋 #
void PCmove(char board[X][Y])
{
srand((unsigned)time(NULL));
while (1)
{
int x = 0;
int y = 0;
x = (rand() % X) + 1;
y = (rand() % Y) + 1;
if (board[x - 1][y - 1] == ' ')
{
board[x - 1][y - 1] = '#';
flag = iswin(board, x, y);
break;
}
}
}
//棋盘是否满了
int Full(char board[X][Y])
{
for (int i = 0; i < X; i++)
{
for (int j = 0; j < Y; j++)
{
if (board[i][j] == ' ') return 0;
}
}
return 1;
}
//判断胜负
char iswin(char board[X][Y], int x, int y)
{
int arr[X][Y] = { 0 };
int way[4] = { 1,1,1,1 };
char c = board[x - 1][y - 1];
system("cls");
printboard(board);
printf("上一步%c下在了%d行%d列\n", c, x, y);
//将该种类型棋子变成0 1混合的int类型数组，1表示该种类型的棋子分布
for (int i = 0; i < X; i++)
{
for (int j = 0; j < Y; j++)
{
if (board[i][j] == c)
{
arr[i][j] = 1;
}
}
}
//校准行列数
x--;
y--;
for (int i = 1; i < NUM; i++)
if (x - i >= 0 && arr[x - i][y] == 1) way[0]++;
for (int i = 1; i < NUM; i++)
if (x + i < X && arr[x + i][y] == 1) way[0]++;
for (int i = 1; i < NUM; i++)
if (y - i >= 0 && arr[x][y - i] == 1) way[1]++;
for (int i = 1; i < NUM; i++)
if (y + i < Y && arr[x][y + i] == 1) way[1]++;
for (int i = 1; i < NUM; i++)
if (x - i >= 0 && y - i >= 0 && arr[x - i][y - i] == 1) way[2]++;
for (int i = 1; i < NUM; i++)
if (x + i < X && y + i < Y && arr[x + i][y + i] == 1) way[2]++;
for (int i = 1; i < NUM; i++)
if (x - i >= 0 && y + i < Y && arr[x - i][y + i] == 1) way[3]++;
for (int i = 1; i < NUM; i++)
if (x + i < X && y - i >= 0 && arr[x + i][y - i] == 1) way[3]++;
if (way[0] == NUM) printf(" ↑↓方向有了%d个棋子\n", way[0]);
if (way[1] == NUM) printf(" ←→方向有了%d个棋子\n", way[1]);
if (way[2] == NUM) printf(" ↖↘方向有了%d个棋子\n", way[2]);
if (way[3] == NUM) printf(" ↙↗方向有了%d个棋子\n", way[3]);
if (way[0] == NUM || way[1] == NUM || way[2] == NUM || way[3] == NUM)
{
printf("达成%d子连珠！\n", NUM);
return board[x][y];
}
return 'a';
}