Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1
and 0
respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is 2
.
Note: m and n will be at most 100.
class Solution {
public:
int uniquePathsWithObstacles(vector<vector<
int> > &obstacleGrid)
{
int m=obstacleGrid.size();
if(m==
0)
return
0;
int n=obstacleGrid[
0].size();
int path[n];
path[
0]=
1-obstacleGrid[
0][
0];
for(
int i=
1;i<n;i++)
if(obstacleGrid[
0][i]==
1) path[i]=
0;
else path[i]=path[i-
1];
for(
int i=
1;i<m;i++)
{
if(obstacleGrid[i][
0]==
1) path[
0]=
0;
for(
int j=
1;j<n;j++)
if(obstacleGrid[i][j]==
1) path[j]=
0;
else path[j]=path[j-
1]+path[j];
}
return path[n-
1];
}
};