poj2853

简单题

View Code

   
     

    
      #include 
    
      <
    
      iostream
    
      >
    
      
#include 
    
      <
    
      cstdlib
    
      >
    
      
#include 
    
      <
    
      cstring
    
      >
    
      
#include 
    
      <
    
      cstdio
    
      >
    
      
#include 
    
      <
    
      cmath
    
      >
    
      

    
      using
    
       
    
      namespace
    
       std;


    
      int
    
       main()
{
 
    
      //
    
      freopen("t.txt", "r", stdin);
    
      

    
       
    
      int
    
       t;
 scanf(
    
      "
    
      %d
    
      "
    
      , 
    
      &
    
      t);
 
    
      while
    
       (t
    
      --
    
      )
 {
 
    
      int
    
       a;
 scanf(
    
      "
    
      %d
    
      "
    
      , 
    
      &
    
      a);
 printf(
    
      "
    
      %d 
    
      "
    
      , a);
 
    
      int
    
       n;
 scanf(
    
      "
    
      %d
    
      "
    
      , 
    
      &
    
      n);
 
    
      int
    
       m 
    
      =
    
       floor(sqrt(n 
    
      *
    
       
    
      2
    
      ));
 
    
      int
    
       ans 
    
      =
    
       
    
      0
    
      ;
 
    
      for
    
       (
    
      int
    
       i 
    
      =
    
       
    
      1
    
      ; i 
    
      <=
    
       m; i
    
      ++
    
      )
 {
 
    
      if
    
       (i 
    
      %
    
       
    
      2
    
       
    
      ==
    
       
    
      0
    
       
    
      &&
    
       n 
    
      %
    
       (i 
    
      /
    
       
    
      2
    
      ) 
    
      ==
    
       
    
      0
    
       
    
      &&
    
       n 
    
      /
    
       (i 
    
      /
    
       
    
      2
    
      ) 
    
      %
    
       
    
      2
    
       
    
      ==
    
       
    
      1
    
      )
 ans
    
      ++
    
      ;
 
    
      if
    
       (i 
    
      %
    
       
    
      2
    
       
    
      ==
    
       
    
      1
    
       
    
      &&
    
       n 
    
      %
    
       i 
    
      ==
    
       
    
      0
    
      )
 ans
    
      ++
    
      ;
 }
 printf(
    
      "
    
      %d\n
    
      "
    
      , ans 
    
      -
    
       
    
      1
    
      );
 }
 
    
      return
    
       
    
      0
    
      ;
}