C语言计算1*2*3+3*4*5+……+99*100*101

#include 



int main () {
  
  int n=1,sum=0,m=0;
  for(n=1;n<=99;n+=2)
    {
      m=n*(n+1)*(n+2);
      sum=sum+m;


    }  
    printf("Sum=%d",sum);

  return 0;
}