【UVa】Headmaster's Headache(状压dp)

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1758

晕。。。。状压没考虑循环方向然后错了好久。。

这点要注意。。。(其实就是01背包变成了完全背包QAQ

我们将课程拆成两个点,然后状压

那么答案就是(1<<(s<<1))-1

转移就不说了,,,,,太简单。。

#include <cstdio>

#include <cstring>

#include <cmath>

#include <string>

#include <iostream>

#include <algorithm>

#include <queue>

#include <set>

#include <map>

using namespace std;

typedef long long ll;

#define pii pair<int, int>

#define pii pair<int, int>

#define mkpii make_pair<int, int>

#define pdi pair<double, int>

#define mkpdi make_pair<double, int>

#define pli pair<ll, int>

#define mkpli make_pair<ll, int>

#define rep(i, n) for(int i=0; i<(n); ++i)

#define for1(i,a,n) for(int i=(a);i<=(n);++i)

#define for2(i,a,n) for(int i=(a);i<(n);++i)

#define for3(i,a,n) for(int i=(a);i>=(n);--i)

#define for4(i,a,n) for(int i=(a);i>(n);--i)

#define CC(i,a) memset(i,a,sizeof(i))

#define read(a) a=getint()

#define print(a) printf("%d", a)

#define dbg(x) cout << (#x) << " = " << (x) << endl

#define error(x) (!(x)?puts("error"):0)

#define printarr2(a, b, c) for1(_, 1, b) { for1(__, 1, c) cout << a[_][__]; cout << endl; }

#define printarr1(a, b) for1(_, 1, b) cout << a[_] << '\t'; cout << endl

inline const int getint() { int r=0, k=1; char c=getchar(); for(; c<'0'||c>'9'; c=getchar()) if(c=='-') k=-1; for(; c>='0'&&c<='9'; c=getchar()) r=r*10+c-'0'; return k*r; }

inline const int max(const int &a, const int &b) { return a>b?a:b; }

inline const int min(const int &a, const int &b) { return a<b?a:b; }



const int N=17, oo=0x3f3f3f3f;

int f[1<<N], n, m, s, sum[N];

struct dat { int c, s; }a[105], b[105];



void readin(dat arr[], int n) {

    for1(i, 1, n) {

        arr[i].s=0; arr[i].c=oo;

        read(arr[i].c); //dbg(arr[i].c);

        char ch=getchar();

        int r=0;

        while(ch!='\n' && ch!='\r') {

            if(ch<'0'||ch>'9') {

                if(r!=0) arr[i].s|=(3<<((r-1)<<1));

                r=0;

                while(ch<'0'||ch>'9') {

                    ch=getchar();

                    if(ch=='\n' || ch=='\r') break;

                }

                if(ch=='\n' || ch=='\r') break;

            }

            r=r*10+ch-'0';

            ch=getchar();

        }

        if(r!=0) arr[i].s|=(3<<((r-1)<<1));

        //rep(k, s) if(arr[i].s&(3<<(k<<1))) printf("%d ", k+1);

        //puts("");

    }

}

void Prin(int x) {

    for3(k, ((s-1)<<1)+1, 0) { printf("%d", (bool)(x&(1<<k))); if((k&1)==0) printf(" "); }

    puts("");

}

int main() {

    read(s); read(n); read(m);

    while(s) {

        int all=(1<<(s<<1))-1;

        CC(f, 0x3f); CC(sum, 0);

        readin(a, n); readin(b, m);



        int tc=0, tn=0;

        for1(i, 1, n) rep(k, s) if((a[i].s>>(k<<1))&3) sum[k]++;

        rep(k, s) if(sum[k]) {

            int t=1;

            if(sum[k]>=2) t=3;

            tc|=(t<<(k<<1));

        }

        for1(i, 1, n) tn+=a[i].c;

        f[tc]=tn;



        for1(i, 1, m) {

            //dbg(i);

            for3(j, all, 0) if(f[j]!=oo) {

            int nx=0; //Prin(j);

            rep(k, s) if(b[i].s&(3<<(k<<1))) {

                int now=(j>>(k<<1))&3;

                if(now==0 || now==2) nx|=1<<(k<<1);

                if(now==1 || now==3) nx|=2<<(k<<1);

            }

            f[j|nx]=min(f[j|nx], f[j]+b[i].c); //Prin(nx); Prin(j|nx); puts("");

        } }

        if(f[all]==oo) f[all]=-1;

        printf("%d\n", f[all]);

        read(s); read(n); read(m);

    }

    return 0;

}

 

  

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