public class MinOfShiftedArray { /** * Q69 旋转数组的最小元素 * 把一个数组最开始的若干个元素搬到数组的末尾,我们称之为数组的旋转。输入一个排好序的数组的一个旋转,输出旋转数组的最小元素。 * 例如数组{3, 4, 5, 1, 2}为{1, 2, 3, 4, 5}的一个旋转,该数组的最小值为1。 */ public static void main(String[] args) { int[][] a={ {1,2,3,4,5}, {2,3,4,5,1}, {3,4,5,1,2}, {4,5,1,2,3}, {5,1,2,3,4}, }; for(int[] each:a){ int min=minOfShiftedArray(each); System.out.println(min); } } /* * Divide and conquer */ public static int minOfShiftedArray(int[] x){ if(x==null||x.length==0){ return -1; } int len=x.length; int low=0; int high=len-1; if(x[low]<x[high]){//if the array is not shifted actually,e.g. {1,2,3,4,5} return x[low]; } int mid=0; while(low<high){ mid=(low&high)+(low^high)/2; if(mid==low){//if there are only two elements left return x[low]<x[high]?x[low]:x[high]; } if(x[mid]>x[low]){ low=mid; }else{ high=mid; } } return x[mid]; } }