HUNNU11354:Is the Name of This Problem
| http://acm.hunnu.edu.cn/online/?action=problem&type=show&id=11354&courseid=0 Problem description |
| The philosopher Willard Van Orman Quine (1908–2000) described a novel method of constructing a sentence in order to illustrate the contradictions that can arise from self-reference. This operation takes as input a single phrase and produces a sentence from that phrase. (The author Douglas R. Hofstadter refers to this process as to Quine a phrase.) We can define the Quine operation like so:
Quine(A) = "A" A In other words, if A is a phrase, then Quine(A) is A enclosed in quotes ("), followed by a space, followed by A. For example: Quine(HELLO WORLD) = "HELLO WORLD" HELLO WORLD Below are some other examples of sentences that can be created by the Quine operation. Note that Quining allows sentences to be indirectly self-referential, such as the last sentence below. "IS A SENTENCE FRAGMENT" IS A SENTENCE FRAGMENT"IS THE NAME OF THIS PROBLEM" IS THE NAME OF THIS PROBLEM"YIELDS FALSEHOOD WHEN QUINED" YIELDS FALSEHOOD WHEN QUINED Your goal for this problem is to take a sentence and decide whether the sentence is the result of a Quine operation. |
| Input |
| The input will consist of a sequence of sentences, one sentence per line, ending with a line that has the single word, END. Each sentence will contain only uppercase letters, spaces, and quotation marks. Each sentence will contain between 1 and 80 characters and will not have any leading, trailing, or consecutive spaces.
You must decide whether each sentence is the result of a Quine operation. To be a Quine, a sentence must match the following pattern exactly:
If it matches this pattern, the sentence is a Quine of the phrase A. Note that phrase A must contain the exact same sequence of characters both times it appears. |
| Output |
| There will be one line of output for each sentence in the data set. If the sentence is the result of a Quine operation, your output should be of the form,
If the sentence is not the result of a Quine operation, your output should be the phrase, not a quine. |
| Sample Input |
| "HELLO WORLD" HELLO WORLD"IS A SENTENCE FRAGMENT" IS A SENTENCE FRAGMENT"IS THE NAME OF THIS PROBLEM" IS THE NAME OF THIS PROBLEM"YIELDS FALSEHOOD WHEN QUINED" YIELDS FALSEHOOD WHEN QUINED"HELLO" I SAIDWHAT ABOUT "WHAT ABOUT"" NO EXTRA SPACES " NO EXTRA SPACES"NO"QUOTES" NO"QUOTES""END |
| Sample Output |
| Quine(HELLO WORLD)Quine(IS A SENTENCE FRAGMENT)Quine(IS THE NAME OF THIS PROBLEM)Quine(YIELDS FALSEHOOD WHEN QUINED)not a quinenot a quinenot a quinenot a quinenot a quine |
| Judge Tips |
| A review of quotation marks in strings: As a reminder, the quotation mark character is a regular character, and can be referred to in C, C++, and Java using the standard single-quote notation, like so:
'"' However, to place a quotation mark inside a double-quoted string in C, C++, and Java, you must place a backslash ( "This quotation mark \" is inside the string""\"""\"SAID SHE\" SAID SHE" |
题意：给出一个字符串，符合"A"A的状况输出Quine(A)，否则输出not a quine
思路：首先从左到右找出第一对双引号里的字符串，然后从右到左找出一个双引号后面的字符串，处理好好比较即可
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
char s1[10005],s2[10005];
char str[20005];
int main()
{
int len,i,l1,l2;
while(gets(str))
{
if(!strcmp(str,"END"))
break;
len = strlen(str);
l1 = l2 = 0;
if(str[0] != '"')//第一个必须为“
{
printf("not a quine\n");
continue;
}
for(i = 1; i<len; i++)//找到第一对引号内的字符串
{
if(str[i]!=34)
s1[l1++] = str[i];
else
{
s1[l1] = '"';
break;
}
}
for(i = len-1; i>=0; i--)//从后面开始找到第一个引号出现的位置为止
{
if(str[i] == ' ' && str[i-1] == '"')
{
s2[l2] = '\0';
break;
}
else
s2[l2++] = str[i];
}
char tem;
for(i = 0; i<l2/2; i++)//翻转字符串
{
tem = s2[l2-1-i];
s2[l2-1-i] = s2[i];
s2[i] = tem;
}
if(!strcmp(s1,s2))
printf("Quine(%s)\n",s1);
else
printf("not a quine\n");
}
return 0;
}