re.sub

re.sub的两种用法

2009-04-25 1:00

sub(pattern, repl, string, count=0)     Return the string obtained by replacing the leftmost     non-overlapping occurrences of the pattern in string by the     replacement repl. repl can be either a string or a callable;     if a callable, it's passed the match object and must return     a replacement string to be used. 先来个简单的 >>> alist '12345678903239892323982392398789' >>> re.sub(r'23', '-', alist) '1-45678903-989--98-9-98789' 再来个复杂点的，注意上面红色的字。 Google网页的中文字符都是用unicode来表示的， 下面用一个丑陋的方法把它转出来。 >>> c '艾莉西亚 凯斯(Alicia Keys)\n- 谷&#274 68;音乐搜索' >>> foo2 = lambda x: unichr(int(x.group(0)[2:7])) >>> print re.sub(r'&#\d+;', foo2, c) 艾莉西亚 凯斯(Alicia Keys) - 谷歌音乐搜索