递归调用第一课——三角形嵌套

很早前做的东西了，早就该发，一直忘记，今天终于想起来了，发上来吧。



代码如下：创建了两个类

第一个类：DrawBoard

import java.awt.FlowLayout;
import java.awt.Graphics;
import javax.swing.JFrame;
public class DrawBoard {
	
	public static void main(String [] args){	
		DrawBoard db = new DrawBoard();
		db.createboard();			
	}
	
	public  void createboard(){
		JFrame jf = new JFrame();
		jf.setSize(600, 600);
		jf.setResizable(false);
		jf.setTitle("套三角");
		jf.setDefaultCloseOperation(3);
		jf.setLayout(new FlowLayout());	
		jf.setVisible(true);
		
		Graphics g = jf.getGraphics();
		boardlistener lis = new boardlistener(g);
		jf.addMouseListener(lis);		
	}
}

第二个类：BoardListener

import java.awt.Graphics;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;

public class BoardListener implements MouseListener{
	Graphics g;
	
	public BoardListener(Graphics g1){
		g=g1;
	}
	public void mouseClicked(MouseEvent arg0) {
		int x1=200,y1=400,x2=400,y2=400,x3=300,y3=227;
		g.drawLine(x1, y1, x2, y2);
		g.drawLine(x2, y2, x3, y3);
		g.drawLine(x1, y1, x3, y3);
		int x4=(x1+x3)/2;int x5=(x2+x1)/2;int x6=(x3+x2)/2;
		int y4=(y1+y3)/2;int y5=(y2+y1)/2;int y6=(y3+y2)/2;
		g.drawLine(x4, y4, x5, y5);
		g.drawLine(x6, y6, x5, y5);
		g.drawLine(x4, y4, x6, y6);
		digui(x3,y3,x4,y4,x6,y6);
		digui(x1,y1,x4,y4,x5,y5);
		digui(x2,y2,x5,y5,x6,y6);

	}

	
	public void mouseEntered(MouseEvent arg0) {
			
	}

	
	public void mouseExited(MouseEvent arg0) {
		
	}

	
	public void mousePressed(MouseEvent arg0) {
		
	}

	
	public void mouseReleased(MouseEvent arg0) {
		
	}
	
	public void digui(int x1,int y1,int x2,int y2,int x3,int y3){

		int m1,n1,m2,n2,m3,n3;
		
		m1=(x1+x2)/2;m2=(x1+x3)/2;m3=(x2+x3)/2;
		n1=(y1+y2)/2;n2=(y1+y3)/2;n3=(y2+y3)/2;
		g.drawLine(m1, n1, m2, n2);
		g.drawLine(m3, n3, m2, n2);
		g.drawLine(m1, n1, m3, n3);
		int p1=Math.abs(m2-m3);
		int p2=Math.abs(m1-m3);
		int p3=Math.abs(m1-m2);
		
		if(p1<=10&&p2<=10&&p3<=10)
			return;	
		else
			digui(m1,n1,x2,y2,m3,n3);
			digui(m2,n2,x3,y3,m3,n3);
			digui(m1,n1,x1,y1,m2,n2);
	}
}