C#实现字符串去重

方法一 注:需要.net 3.5框架的支持

string s = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
s = string.Join(",", s.Split(',').Distinct().ToArray());

方法二

复制代码
class Program
{
static void Main(string[] args)
{
string result="";
string str = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
ArrayList list = array(str);
for (int i = 0; i < list.Count;i++)
{
if (i == list.Count - 1)
{
result += list[i];
}
else
{
result += list[i] + ",";
}
}
Console.WriteLine(result);

Console.ReadKey();
}

static ArrayList array(string str)
{
ArrayList aimArr = new ArrayList();
ArrayList strArr = new ArrayList();
string [] strs=str.Split(',');
foreach (string s in strs)
{
strArr.Add(s);
}
for (int i = 0; i < strs.Length; i++)
{
if (!aimArr.Contains(strs[i]))
{
aimArr.Add(strs[i]);
}
}
return aimArr;
}
}

//101,102,103,104,105,106,107,108
复制代码

方法三:使用正则

            string input = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
input = Regex.Replace(input + ",", @"(?:([^,]+,))(?=.*?\1)", "");
Console.WriteLine(input.Substring(0,input.Length-1));

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