现在反向测试Group是否能关联User存储。
User.java: package cn.edu.hpu.one2many; import javax.persistence.CascadeType; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.ManyToOne; import javax.persistence.Table; @Entity @Table(name="m_user") public class User { private int id; private String name; private Group group; //只要有双向就要指定制定一个属性(mapedby) //不指定的话会有两个相同的字段产生 @ManyToOne(cascade={CascadeType.ALL}) public Group getGroup() { return group; } public void setGroup(Group group) { this.group = group; } @Id @GeneratedValue public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } }
Group.java:
package cn.edu.hpu.one2many; import java.util.HashSet; import java.util.Set; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.OneToMany; import javax.persistence.Table; @Entity @Table(name="m_group") public class Group { private int id; private String name; private Set<User> users=new HashSet<User>(); //选择set的原因是因为,set互相之间不会有重复的 //跟数据库模型比较匹配 @Id @GeneratedValue public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } @OneToMany(mappedBy="group") public Set<User> getUsers() { return users; } public void setUsers(Set<User> users) { this.users = users; } }
@Test public void testSaveGroup(){ User u1=new User(); u1.setName("u1"); User u2=new User(); u2.setName("u2"); Group g=new Group(); g.setName("g1"); g.getUsers().add(u1);//users是一个map容器 g.getUsers().add(u2); sessionFactory=new AnnotationConfiguration().configure().buildSessionFactory(); Session s=sessionFactory.openSession(); s.beginTransaction(); s.save(g); //s.save(u); s.getTransaction().commit(); }
@OneToMany(mappedBy="group", cascade={CascadeType.ALL} ) public Set<User> getUsers() { return users; }
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