Oracle SQL 语句中对Like的优化(转自http://blog.yesky.com/52/eric1945/1671052.shtml)

Oracle SQL 语句中对Like的优化

1、尽量不要使用 like '%..%'

2、对于 like '..%..' (不以 % 开头),Oracle可以应用 colunm上的index

3、对于 like '%...' 的 (不以 % 结尾),可以利用 reverse + function index 的形式,变化成 like '..%' 代码

 

建测试表和Index。

注意:重点在于带reverse的function index。同时,一定要使用CBO才行......

 

SQL> select reverse('123') from dual;

REVERSE('123')

--------------------------------

321

1 row selected.

 

SQL> create table test_like as select object_id,object_name from dba_objects;

Table created.

 

SQL> create index test_like__name on test_like(object_name);

Index created.

 

SQL> create index test_like__name_reverse on test_like(reverse(object_name));

Index created.

 

SQL> analyze table test_like compute statistics for table for all indexes;

Table analyzed.

 

SQL> set autot trace

 

--常量开头的like , 会利用index ,没问题......

SQL> select * from test_like where object_name like AS%';

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=2 Card=655 Bytes=15720)

1 0 TABLE ACCESS (BY INDEX ROWID) OF 'TEST_LIKE' (Cost=2 Card=655Bytes=15720)

2 1 INDEX (RANGE SCAN) OF 'TEST_LIKE__NAME' (NON-UNIQUE) (Cost=2 Card=118)

 

-- 开头和结尾都是%,对不起,很难优化

 

SQL> select * from test_like where object_name like '%%';

 

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=6 Card=655 Bytes=15720)

1 0 TABLE ACCESS (FULL) OF 'TEST_LIKE' (Cost=6 Card=655 ytes=15720)

 

-- 以常量结束,直接写的时候是不能应用index的

SQL> select * from test_like where object_name like '%S';

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=6 Card=655 Bytes=15720)

1 0 TABLE ACCESS (FULL) OF 'TEST_LIKE' (Cost=6 Card=655 Bytes=15720)

 

--'以常量结束的,加个reverse 函数,又可以用上index了'

SQL> select * from test_like where reverse(object_name)like reverse('%AS');

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=2 Card=655 Bytes=15720)

1 0 TABLE ACCESS (BY INDEX ROWID) OF 'TEST_LIKE' (Cost=2 Card=655 Bytes=15720)

2 1 INDEX (RANGE SCAN) OF 'TEST_LIKE__NAME_REVERSE' (NON-UNIQUE) (Cost=2 Card=118)

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