POJ 1873 The Fortified Forest

题意:砍掉一些树,用来围剩下的树,要使能包围的请款下,剩下树的价值最大,

思路:二进制枚举所有可能的情况,用凸包找包围的最短长度。

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>
#include <stack>
using namespace std;
const int N = 19;
const double EPS = 1e-12;
struct cpoint{
    double x,y;
    int I;
    double len,val;
    void get(){scanf("%lf%lf%lf%lf",&x,&y,&val,&len);}
    cpoint(double a,double b){x=a,y=b;}
    cpoint(){}
    bool operator<(const cpoint t) const{
        return y<t.y||(y==t.y&&x<t.x);
    }
};
double dist(cpoint a,cpoint b){
    return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));
}
double x_mult(cpoint a,cpoint b,cpoint c){
    return (a.x-c.x)*(b.y-c.y)-(a.y-c.y)*(b.x-c.x);
}
int n;
int cmp(const cpoint a,const cpoint b){
    return a.y<b.y||(a.y==b.y&&a.x<b.x);
}
cpoint re[N],tu[N];
int tmp[N];
double ans ,relen, Val;
int tans;
bool visit[N];
int granham(cpoint p[],int s,cpoint r[]){
    int i,len,top=1;
    sort(p,p+s,cmp);
    r[0] = p[0];r[1] = p[1];r[2] = p[2];
    if(s<3) return s;
    for(i=2;i<s;i++){
        while(top&&x_mult(p[i],r[top],r[top-1])>EPS) top--;
        r[++top] = p[i];
    }
    len = top;r[++top] = p[s-2];
    for(i=s-3;i>=0;i--){
        while(top!=len&&x_mult(p[i],r[top],r[top-1])>EPS) top--;
        r[++top] = p[i];
    }
    return top;
}
void solve(int m)
{
    memset(visit,0,sizeof(visit));
    double ret=0;
    int trees=0,cnt=0;
    relen = 0;
    cpoint p[N];
    for(int i=0;i<n;i++)
    if(m&(1<<i))
    {
        visit[i] = true;
        relen +=re[i].len;
        trees++;
    }else p[cnt++] = re[i],ret+=re[i].val;
    int  k = granham(p,cnt,tu);
    double c=0;

    if(k==2)
    c=2*dist(tu[0],tu[1]);
    else if(k<=1)
    c = 0;
    else
    for(int i=0;i<k;i++)
    c+=dist(tu[i],tu[i+1]);
    if(relen>=c)
    {
        if(Val<ret)
        {
            Val=ret;
            ans = relen-c;
            tans = trees;
            int k=0;
            for(int i=0;i<n;i++)
            if(visit[i]) tmp[k++] = re[i].I;
        }
    }
}

int main()
{
    freopen("in.txt","r",stdin);
    int T = 1;
    while(~scanf("%d",&n)&&n)
    {
        Val = -1;
        for(int i=0;i<n;i++) re[i].get(),re[i].I = i+1;
        sort(re,re+n);
        ans = 1e20;tans = 100;
        for(int i=0;i<(1<<n);i++)
        solve(i);
        printf("Forest %d\n",T++);
        printf("Cut these trees:");
        sort(tmp,tmp+tans);
        for(int i=0;i<tans;i++) printf(" %d",tmp[i]);
        printf("\n");
        printf("Extra wood: %.2lf\n\n",ans);
    }
    return 0;
}


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