USACO chapter2 section 2 Preface Numbering

USACO chapter2 section 2 Preface Numbering

USER: tian tianbing [tbbd4261]
TASK: preface
LANG: C++
Compiling...
Compile: OK
Executing...
Test 1: TEST OK [0.022 secs, 3012 KB]
Test 2: TEST OK [0.000 secs, 3012 KB]
Test 3: TEST OK [0.022 secs, 3012 KB]
Test 4: TEST OK [0.011 secs, 3012 KB]
Test 5: TEST OK [0.000 secs, 3012 KB]
Test 6: TEST OK [0.011 secs, 3012 KB]
Test 7: TEST OK [0.011 secs, 3012 KB]
Test 8: TEST OK [0.011 secs, 3012 KB]
All tests OK.
Your program ('preface') produced all correct answers!  This is your
submission #9 for this problem.  Congratulations!

Here are the test data inputs:

------- test 1 -------
1
------- test 2 -------
20
------- test 3 -------
100
------- test 4 -------
500
------- test 5 -------
1000
------- test 6 -------
2974
------- test 7 -------
3213
------- test 8 -------
3499

Keep up the good work!

Thanks for your submission!

之所以提交了9次，就是因为代码中有system("pause"); 没编译错误，没提示 搞死了！！
不过还好做出来了，浪费了很多时间

/*
ID:tbbd4261
PROG:preface
LANG:C++
*/

#include < fstream >
using   namespace  std;

ifstream  fin( " preface.in " );
ofstream  fout( " preface.out " );
 
   //         {"","I","II","III","IV","V","VI","VII","VIII","IX"},
   //         {"","X","XX","XXX","XL","L","LX","LXX","LXXX","XC"},
   //         {"","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"},
   //         {"","M","MM","MMM"}

int  cg[ 7 ][ 10 ] =  {{ 0 , 1 , 2 , 3 , 1 , 0 , 1 , 2 , 3 , 1 },   // I
                { 0 , 0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 0 },   // V
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 1 }, // X
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // L
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // C
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // D
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 } // M
                };
int  cs[ 7 ][ 10 ] =  {
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // I
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // V
                { 0 , 1 , 2 , 3 , 1 , 0 , 1 , 2 , 3 , 1 }, // X
                { 0 , 0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 0 }, // L
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 1 }, // C
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // D
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 } // M
               };
  int  cb[ 7 ][ 10 ] = {
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // I
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // V
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // X
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 }, // L
                { 0 , 1 , 2 , 3 , 1 , 0 , 1 , 2 , 3 , 1 }, // C
                { 0 , 0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 0 }, // D
                { 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 1 } // M
                };
  int  cq[ 7 ][ 4 ] = {
                { 0 , 0 , 0 , 0 }, // I
                { 0 , 0 , 0 , 0 }, // V
                { 0 , 0 , 0 , 0 }, // X
                { 0 , 0 , 0 , 0 }, // L
                { 0 , 0 , 0 , 0 }, // C
                { 0 , 0 , 0 , 0 }, // D
                { 0 , 1 , 2 , 3 } // M
     };

int  main()
{
     int  n,cnt0 = 0 ,cnt1 = 0 ,cnt2 = 0 ,cnt3 = 0 ,cnt4 = 0 ,cnt5 = 0 ,cnt6 = 0 ;
    fin >> n;    
     for ( int  i = 1 ; i <= n; i ++ )
    {
            cnt0 += cg[ 0 ][i % 10 ];
            cnt1 += cg[ 1 ][i % 10 ];
            cnt2 += cg[ 2 ][i % 10 ] + cs[ 2 ][(i / 10 ) % 10 ];
            cnt3 += cs[ 3 ][(i / 10 ) % 10 ];
            cnt4 += cs[ 4 ][(i / 10 ) % 10 ] + cb[ 4 ][(i / 100 ) % 10 ];
            cnt5 += cb[ 5 ][(i / 100 ) % 10 ];
            cnt6 += cb[ 6 ][(i / 100 ) % 10 ]  +  cq[ 6 ][(i / 1000 ) % 10 ]; 
    }
     if (cnt0)fout << " I  " << cnt0 << endl;
     if (cnt1)fout << " V  " << cnt1 << endl;
     if (cnt2)fout << " X  " << cnt2 << endl;
     if (cnt3)fout << " L  " << cnt3 << endl;
     if (cnt4)fout << " C  " << cnt4 << endl;
     if (cnt5)fout << " D  " << cnt5 << endl;
     if (cnt6)fout << " M  " << cnt6 << endl;
     // system("pause");  
     return   0 ;
}