linux和android端的pthread学习

本文起初主要想写个示例实测下pthread_mutex_lock和pthread_mutex_trylock区别。在linux机器上很快就over了,但是想了一下,pthread是unix系的,在windows没办法直接运行代码很不方便。于是想到了android,windows上安装ndk,手机root就可以跑pthread代码咯。。。

demo

lock和trylock的区别也很好理解:,前者是阻塞的,死等知道互斥锁被释放;而后者则更加灵活, 浅尝辄止,做个尝试不行则干其他事情去。。测试代码pt_lock.c如下:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <pthread.h>
#include <unistd.h>
#include <sys/types.h>

typedef pthread_t pt_t;
typedef unsigned int uint_t;

pthread_mutex_t mt = PTHREAD_MUTEX_INITIALIZER;

void lock_func(void* arg)
{
	pid_t pid;	//process
	pt_t tid;	// thread
	
	pid = getpid();
	tid = pthread_self();

	printf("want to lock mutex, msg=%s, tid=%u\n", (char*)arg, (uint_t)tid);
	
	pthread_mutex_lock( &mt );
	printf("I[tid=%u] am using, (*|^_^|*)\n", (uint_t)tid);
	sleep(10);
	pthread_mutex_unlock( &mt );
}

void try_lock_func(void* arg)
{
	uint_t tid = (uint_t)pthread_self();
	int counter = 0;
	
	while ( pthread_mutex_trylock( &mt ) )
	{
		sleep(1);
		++counter;
		
		printf("after sleep 1s, i [tid=%u] want to try again, iter=%d.\n", tid, counter);
	}
	printf("It is my[tid=%u] turn, so long i waited...msg=%s\n", tid, (char*)arg);
	pthread_mutex_unlock( &mt );	
}

#define XX_CREATE_FAILED(err)	\
	printf("create thread error : %s\n", strerror(err));\
	return 1;	

int main()
{
	int rc;
	pt_t pt1, pt2, pt3;
	
	const char* msg1 = "block";
	const char* msg2 = "unblock";
	
	rc = pthread_create(&pt1, NULL, (void*)&lock_func, (void*)msg1);	if (rc != 0) 
	{
		XX_CREATE_FAILED(rc);
	}
	
	rc = pthread_create(&pt2, NULL, (void*)&lock_func, (void*)msg1);	if (rc != 0)
	{
		XX_CREATE_FAILED(rc);
	}
	sleep(1);
	
	rc = pthread_create(&pt3, NULL, (void*)&try_lock_func, (void*)msg2);	if (rc != 0)
	{
		XX_CREATE_FAILED(rc);
	}
	
	pthread_join(pt1, NULL);
	pthread_join(pt2, NULL);
	pthread_join(pt3, NULL);	
	return 0;
}
代码思路也很好理解:创建三个线程,1和2通过lock方式去争抢mt互斥锁,3线程则灵活,每隔1秒去检测下mt互斥锁是否可以用,不会阻塞。线程1或者2占有mt的时间为10秒。

linux run

xx@h10-1-152-72:~/peteryfren/cpp/pthread> gcc -Wall -o pt_lock pt_lock.c -lpthread
xx@h10-1-152-72:~/peteryfren/cpp/pthread> ./pt_lock 
输出结果与预期一致,id=1082132800线程先占有mt,10s内线程tid=1090525504阻塞,而线程tid=1098918208每隔1s测试下mt可用性。
want to lock mutex, msg=block, tid=1082132800
I[tid=1082132800] am using, (*|^_^|*)
want to lock mutex, msg=block, tid=1090525504
after sleep 1s, i [tid=1098918208] want to try again, iter=1.
after sleep 1s, i [tid=1098918208] want to try again, iter=2.
after sleep 1s, i [tid=1098918208] want to try again, iter=3.
after sleep 1s, i [tid=1098918208] want to try again, iter=4.
after sleep 1s, i [tid=1098918208] want to try again, iter=5.
after sleep 1s, i [tid=1098918208] want to try again, iter=6.
after sleep 1s, i [tid=1098918208] want to try again, iter=7.
after sleep 1s, i [tid=1098918208] want to try again, iter=8.
I[tid=1090525504] am using, (*|^_^|*)
after sleep 1s, i [tid=1098918208] want to try again, iter=9.
after sleep 1s, i [tid=1098918208] want to try again, iter=10.
after sleep 1s, i [tid=1098918208] want to try again, iter=11.
after sleep 1s, i [tid=1098918208] want to try again, iter=12.
after sleep 1s, i [tid=1098918208] want to try again, iter=13.
after sleep 1s, i [tid=1098918208] want to try again, iter=14.
after sleep 1s, i [tid=1098918208] want to try again, iter=15.
after sleep 1s, i [tid=1098918208] want to try again, iter=16.
after sleep 1s, i [tid=1098918208] want to try again, iter=17.
after sleep 1s, i [tid=1098918208] want to try again, iter=18.
after sleep 1s, i [tid=1098918208] want to try again, iter=19.
It is my[tid=1098918208] turn, so long i waited...msg=unblock

android run

android上编译和运行pt_lock参考前一篇blog: http://blog.csdn.net/ryfdizuo/article/details/28891649   具体批处理run.cmd如下:
@echo "1. build .o file"

@Rem fPIE flag is used in compiling stage.
D:\android-ndk-r9b-windows-x86\toolchains\arm-linux-androideabi-4.6\prebuilt\windows\bin\arm-linux-androideabi-gcc.exe --sysroot=D:\android-ndk-r9b-windows-x86\platforms\android-13\arch-arm -fPIE -c pt_lock.c

@echo "2. build exec file"

@Rem pie flag is used in linking stage.
D:\android-ndk-r9b-windows-x86\toolchains\arm-linux-androideabi-4.6\prebuilt\windows\bin\arm-linux-androideabi-gcc.exe --sysroot=D:\android-ndk-r9b-windows-x86\platforms\android-13\arch-arm -pie -o pt_lock pt_lock.o

@pause
里面的gcc和android系统库路径需要根据机器上实际位置修改。
注意android上gcc编译与linux上有点点差别:ndk中gcc不需要需要显式指定-lpthread。可能pthread默认就会链接。android-ndk-r9b-windows-x86\platforms\android-13\arch-arm\usr\lib目录下的这些so加载需要指定。。在Android.mk中类似。
命令行下运行run.cmd,编译pt_lock,然后推到手机上,注意我的nexus4必须是/data/local/tmp下面才有权限,运行后有错误,具体步骤:
E:\GitHub\ndk_tutorial\pthread_playground>adb shell
root@mako:/ # cd /data/local/tmp
cd /data/local/tmp
root@mako:/data/local/tmp # mv /sdcard/pt_lock ./
mv /sdcard/pt_lock ./
root@mako:/data/local/tmp # chmod 751 pt_lock
chmod 751 pt_lock
root@mako:/data/local/tmp # ./pt_lock
error: only position independent executables (PIE) are supported.
报了PIE不支持的错误,n4上安装的是android L系统,gg后知道编译的链接的需要增加pie等设置,参见[ref2],fPIE是编译时候的选项,pie是链接时候的选项,再次重新编译,推到手机上运行OK。。。pt_lock.c不需要做任何修改。

pthread学习

1.线程相关
1)回调函数类型 void* (*pfunc) (void* arg) ,参数通过void*传入,多个参数是通过结构体/数组打包。
2)线程属性,可以设置线程类型,一般是joinable,设置线程栈的大小。如果线程内部要定义大数组一定小心栈越界。
3)线程终止的几种情况:
  • 回调函数运行完成,正常退出
  • 线程内调用pthread_exit函数,不管是否完成都退出。该函数后面的所有代码都不会被执行(尤其printf等语句)。
  • 其他线程显式调用pthread_cancel 结束当前线程。
  • 整个进程被终止,因为调用了exit等函数。它下面的所有线程都被杀死,资源被回收。
  • main函数创建N个线程,两种做法等待其他线程结束:显式pthread_join等待其他线程结束;main函数中调用pthread_exit,等待其他线程结束。
2. 互斥锁相关
pthread_mutex_init
pthread_mutex_lock,阻塞等待
pthread_mutex_trylock,非阻塞等待
pthread_mutex_destroy

3. 信号量相关
pthread_mutex_init
pthread_mutex_wait 阻塞当前线程,直到满足某些条件时,伪代码如下:
begin
pthread_mutex_unlock( mutex )  阻塞之前释放互斥锁
block_on_cond( condition ) 条件阻塞
pthread_mutex_lock(mutex) 条件满足后 占有互斥锁,完成工作后需要释放互斥锁
end
该语句必须在循环中执行,而不是if中,因为线程之间可能有虚假的唤醒行为,spurious wakeup。当唤醒时需要再次确定预期的条件是否满足,如果不满足继续等待。相关的讨论参见: http://a-shi.org/blog/2012/07/27/pthread_cond_wait_mutex_while/

pthread_mutex_signal,只有一个线程等待时发送信号量
pthread_mutex_broadcast 多个线程同时等待时使用
pthread_mutex_destroy

4. 生存者/消费者,读写,哲学家进餐模型
http://www.cs.nmsu.edu/~jcook/Tools/pthreads/examples.html

refer

1. gcc下面的pie和fPIE 选项标志讲解,http://richardustc.github.io/blog/2013/05/pie/

2. android L系统下PIE错误,http://blog.csdn.net/hxdanya/article/details/39371759

3. pthread http://man7.org/linux/man-pages/man3/pthread_create.3.html


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