Reverse Number
http://acm.hdu.edu.cn/showproblem.php?pid=1266
Time Limit: 2000/1000 MS (Java/Others)
Memory Limit: 65536/32768 K (Java/Others)
Problem Description
Welcome to 2006'4 computer college programming contest!
Specially, I give my best regards to all freshmen! You are the future of HDU ACM! And now, I must tell you that ACM problems are always not so easy, but, except this one... Ha-Ha!
Give you an integer; your task is to output its reverse number. Here, reverse number is defined as follows:
1. The reverse number of a positive integer ending without 0 is general reverse, for example, reverse (12) = 21;
2. The reverse number of a negative integer is negative, for example, reverse (-12) = -21;
3. The reverse number of an integer ending with 0 is described as example, reverse (1200) = 2100.
Input
Input file contains multiple test cases. There is a positive integer n (n<100) in the first line, which means the number of test cases, and then n 32-bit integers follow.
Output
For each test case, you should output its reverse number, one case per line.
Sample Input
Sample Output
水。
完整代码:
/*0ms,208KB*/
#include<cstdio>
#include<cstring>
char s[15];
void solve(char* s)
{
int i, j, len = strlen(s);
for (i = len - 1; i > 0; --i)
if (s[i] != '0') break;
for (j = i; j >= 0; --j) putchar(s[j]);
puts(s + i + 1);
}
int main()
{
int t;
scanf("%d\n", &t);
while (t--)
{
gets(s);
if (s[0] == '-')
{
putchar('-');
solve(s + 1);
}
else solve(s);
}
return 0;
}