hdu 1062 Text Reverse 字符串处理。简单水题

Text Reverse

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 18667    Accepted Submission(s): 7030

Problem Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.

 

Output

For each test case, you should output the text which is processed.

 

Sample Input

   
   
   
   

    
    
    
    3
olleh !dlrow
m'I morf .udh
I ekil .mca
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    hello world!
I'm from hdu.
I like acm.


    
    
    
    
 
     
 
      Hint 
     
 Remember to use getchar() to read '\n' after the interger T, then you may use gets() to read a line and process it. 
    
    
    
    
     
   
   
   
   

 

没什么好说的。

代码：

#include <stdio.h>
#include <string.h>

int main()
{
	int t ;
	scanf("%d",&t);
	getchar() ;
	while(t--)
	{
		char line[1010] , temp[1010];
		gets(line) ;
		int len = strlen(line) , j = 0 ;
		for(int i = 0 ; i <= len ; ++i)
		{
			if(line[i] == ' '|| line[i] == '\0')
			{
				j = 0 ;
				strrev(temp) ;
				if(line[i] == ' ')
					printf("%s ",temp) ;
				else
					printf("%s",temp) ;
				temp[0]='\0' ;
			}
			else
			{
				temp[j++] = line[i] ;
				temp[j] = '\0' ;
			}
		}
		puts("") ;
	}
	return 0 ;
}

与君共勉