Hibernate构造器查询，字段中有日期报org.hibernate.hql.PARSER Unable to locate appropriate cons

解决方案： Dao: super.getHibernateTemplate().find("select new Student(id,name,date) from Student"); 实体类： public class Student { private Long id; private String name; private String address; private Timestamp date; public Long getId() {    return id; } public void setId(Long id) {    this.id = id; } public String getName() {    return name; } public void setName(String name) {    this.name = name; } public String getAddress() {    return address; } public void setAddress(String address) {    this.address = address; } public Timestamp getDate() {    return date; } public void setDate(Timestamp date) {    this.date = date; } public Student() {    super(); } //注意些处的构造方法 public Student(Long id, String name, Object date) { this.id=id;    this.name = name;    this.date = stringToTimestamp(date.toString()); } /** * 字符串转换为Timestamp * @param dateStr * @return */ public static Timestamp stringToTimestamp(String dateStr){       SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");    Calendar cal = Calendar.getInstance();    try {     Date date = sdf.parse(dateStr);     date.getTime();     cal.setTime(date);     return new Timestamp(cal.getTimeInMillis());    } catch (ParseException e) {     e.printStackTrace();    }       cal.setTime(new Date());    return new Timestamp(cal.getTimeInMillis()); } }