按内容截取行中的某字段（列）

1.按分隔符截取

 例如，截取有固定格式的日志

#cat myfile

2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,PUB_ID:3837482931,phone:372901111

2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,PUB_ID:3837482931,phone:372901111

2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,PUB_ID:3837482931,phone:372901111

#cat myfile | awk -F' ClientLog---> ' '{print $2}'|awk -F',' '{print $1":"$3}'|awk -F':' '{print $2 $4}'

123212342,3837482931

123212342,3837482931

123212342,3837482931

2.按内容截取

例如，要截取myfile日志中uuid内容和PUB_ID内容，字段长度固定，位置不确定：

# cat myfile

 2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,PUB_ID:3837482931,phone:372901111

2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,PUB_ID:3837482931,phone:372901111

2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,PUB_ID:3837482931,phone:372901111

2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,phone:372901111,PUB_ID:3837482931,

2012-01-12 23:00:00 org.umessage.subway.ClientLog--->uuid:123212342,pid:ewldkjf,PUB_ID:3837482931,phone:372901111

# cat  myfile  |  sed 's/ .*uuid:\(.........\).*PUB_ID:\(..........\).*/\1 ,\2/'

123212342,3837482931

123212342,3837482931

123212342,3837482931

123212342,3837482931

123212342,3837482931

sed命令解释：意思是所有把匹配 .*uuid:\(.........\).*PUB_ID:\(..........\).*的行替换成被匹配到的括号中的内容输出；

其中各选项参数以/分割，s表示替换，\1表示前面将被替换的正则表达式中第一个括号里的内容，\n表示第n组的内容，  .表示匹配任意一个字符，*表示前面项匹配任意次

参考：http://www.iteye.com/topic/587673

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