LeetCode Trapping Rain Water

Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.

For example,
Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6.


The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped. Thanks Marcos for contributing this image!

class Solution {
public:
    int trap(int A[], int n) {
        if(NULL == A || 0 == n)
    		return 0;
		vector<int> left(n);
		int maxHeight = 0;
		for(int i = 0; i < n; ++i)
		{
			left[i] = maxHeight;
			maxHeight = max(maxHeight, A[i]);
		}
		maxHeight = 0;
		vector<int> right(n);
		for(int i = n - 1; i >= 0; --i)
		{
			right[i] = maxHeight;
			maxHeight = max(maxHeight, A[i]);
		}
		int sum = 0;
		int height = 0;
		for(int i = 0; i < n; ++i)
		{
			height = min(left[i], right[i]) - A[i];
			sum += height > 0? height: 0;
		}
		return sum;
    }
};



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