【题目大意】:给出一些点,求凸包周长,并加上给定圆周长
【解题思路】:极角排序,然后求凸包。模版testing
【代码】:
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <vector> #include <queue> #include <cmath> #include <string> #include <cctype> #include <map> #include <iomanip> using namespace std; #define eps 1e-8 #define PI acos(-1.0) #define inf 1<<30 #define linf 1LL<<60 #define pb push_back #define lc(x) (x << 1) #define rc(x) (x << 1 | 1) #define lowbit(x) (x & (-x)) #define ll long long #define INF 999999999.9 struct Point{ double x, y, dis; }pt[1005],stack[1005],p0; int top,tot; int n; double l; //计算几何距离 double get_dis(double x1, double y1, double x2, double y2){ return sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); } //极角比较, 返回-1: p0p1在p0p2的右侧,返回0:p0,p1,p2共线 int Cmp_PolarAngel(struct Point p1, struct Point p2, struct Point pb){ double delta=(p1.x-pb.x)*(p2.y-pb.y)-(p2.x-pb.x)*(p1.y-pb.y); if (delta<0.0) return 1; else if (delta==0.0) return 0; else return -1; } // 判断向量p2p3是否对p1p2构成左旋 bool Is_LeftTurn(struct Point p3, struct Point p2, struct Point p1){ int type=Cmp_PolarAngel(p3, p1, p2); if (type<0) return true; return false; } //先按极角排,再按距离由小到大排 int Cmp(const void*p1, const void*p2){ struct Point*a1=(struct Point*)p1; struct Point*a2=(struct Point*)p2; int type=Cmp_PolarAngel(*a1, *a2, p0); if (type<0) return -1; else if (type==0){ if (a1->dis<a2->dis) return -1; else if (a1->dis==a2->dis) return 0; else return 1; } else return 1; } //求凸包 void Solve(int n){ int k; p0.x=p0.y=INF; for (int i=0; i<n; i++){ scanf("%lf %lf",&pt[i].x, &pt[i].y); if (pt[i].y < p0.y){ p0.y=pt[i].y; p0.x=pt[i].x; k=i; } else if (pt[i].y==p0.y){ if (pt[i].x<p0.x){ p0.x=pt[i].x; k=i; } } } pt[k]=pt[0]; pt[0]=p0; for (int i=1; i<n; i++) pt[i].dis=get_dis(pt[i].x,pt[i].y,p0.x,p0.y); qsort(pt+1, n-1, sizeof(struct Point), Cmp); //去掉极角相同的点 tot=1; for (int i=2; i<n; i++) if (Cmp_PolarAngel(pt[i], pt[i-1], p0)) pt[tot++]=pt[i-1]; pt[tot++]=pt[n-1]; //求凸包 top=1; stack[0]=pt[0]; stack[1]=pt[1]; for (int i=2; i<tot; i++){ while (top>=1 && Is_LeftTurn(pt[i],stack[top],stack[top-1])==false) top--; stack[++top]=pt[i]; } stack[top+1]=stack[0]; double ans=0; ans=2.0*PI*(double)l; for (int i=1; i<=top+1; i++){ ans+=get_dis(stack[i-1].x,stack[i-1].y,stack[i].x,stack[i].y); } printf("%.0f\n",ans); } int main(){ while (~scanf("%d%lf",&n,&l)){ Solve(n); } return 0; }