POJ 题目1001 ,hdu1753 （大数，Java简单题）

http://poj.org/problem?id=1001

题目大意： 求R^n ,  输出 ： 前面的0不输出，后面的零不输出

 

stripTrailingZeros();//末尾除零

 toPlainString();     //返回不带指数字段的此 BigDecimal 的字符串表示形式

 

package com.hdu;

import java.math.BigDecimal;
import java.util.Scanner;

public class POJ1001 {
	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		while(cin.hasNext()){
			BigDecimal r = cin.nextBigDecimal();
			int n = cin.nextInt();
			BigDecimal ans = r.pow(n).stripTrailingZeros();//除去后面多余的0
			System.out.println(ans.toPlainString().replaceAll("^0", ""));
		}
	}
}


/*
Sample Input


95.123 12
0.4321 20
5.1234 15
6.7592  9
98.999 10
1.0100 12


Sample Output


548815620517731830194541.899025343415715973535967221869852721
.00000005148554641076956121994511276767154838481760200726351203835429763013462401
43992025569.928573701266488041146654993318703707511666295476720493953024
29448126.764121021618164430206909037173276672
90429072743629540498.107596019456651774561044010001
1.126825030131969720661201
 
 */

http://acm.hdu.edu.cn/showproblem.php?pid=1753

最后输出要加 toPlainString(); 否则WA

package com.hdu;

import java.math.BigDecimal;
import java.util.Scanner;

public class hdu1753 {

	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		while(cin.hasNext()){
			BigDecimal a = cin.nextBigDecimal();
			BigDecimal b = cin.nextBigDecimal();
			a = a.add(b);
			System.out.println(a.stripTrailingZeros().toPlainString());
		}
			
	}
}
/*
Sample Input
1.1 2.9
1.1111111111 2.3444323343
1 1.1
 

Sample Output
4
3.4555434454
2.1

 * */