Java BeansZOJ Problem Set - 3714 the 10th 浙江ACM赛

Java Beans Time Limit: 2 Seconds Memory Limit: 65536 KB

There are N little kids sitting in a circle, each of them are carrying some java beans in their hand. Their teacher want to selectM kids who seated in M consecutive seats and collect java beans from them.

The teacher knows the number of java beans each kids has, now she wants to know the maximum number of java beans she can get fromM consecutively seated kids. Can you help her?

Input

There are multiple test cases. The first line of input is an integer T indicating the number of test cases.

For each test case, the first line contains two integers N (1 ≤ N ≤ 200) andM (1 ≤ M ≤ N). Here N and M are defined in above description. The second line of each test case containsN integers C_i (1 ≤ C_i ≤ 1000) indicating number of java beans thei^th kid have.

Output

For each test case, output the corresponding maximum java beans the teacher can collect.

Sample Input

2
5 2
7 3 1 3 9
6 6
13 28 12 10 20 75

Sample Output

16
158

#include<stdio.h>
int main()
{
	int T,N,M,i,j;
    int arr[440];
	int max=-1,sum;
	scanf("%d",&T);

	while(T--)
	{sum=0;max=-1;

		scanf("%d%d",&N,&M);
		for(i=0;i<N;i++)
		{	scanf("%d",&arr[i]);
		    arr[i+N]=arr[i];
		}
       for(i=0;i<N;i++)	   
	   {sum=0;
		   for(j=i;j<i+M;j++)
			   sum+=arr[j];
		   if(sum>max)
			   max=sum;
	   }
		printf("%d\n",max);
	}
 return 0;
}