1065. A+B and C (64bit)

1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

Tip：其实long long就可以满足了。切记分析正溢出和负溢出就可以了。

#include<stdio.h>

bool check(long long a, long long b, long long c)
{
	long long sum;
	sum = a + b;
	//正数相加溢出 
	if(a > 0 && b > 0 && sum <= 0)
		return true;
	//负数相加溢出 
	else if(a < 0 && b < 0 && sum >= 0) 
		return false;
	else
		return sum > c;
}
int main()
{
//	freopen("F://Temp/input.txt", "r", stdin);
	int n;
	scanf("%d", &n);
	for(int i = 0; i < n; i ++)
	{
		long long a, b, c;
		scanf("%lld%lld%lld", &a, &b, &c);
		printf("Case #%d: %s\n", i + 1, (check(a, b, c) ? "true" : "false"));
	}
	return 0;
}