题意:求函数F(x) = max(S(x)) 的最小值。S(x) = a*x^2 + b*x + c(0 ≤ a ≤ 100),输入多个S(x)。
题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=493&problem=4222
——>>做的第一道三分题,先找出F(x),然后三分,迭代100次。
#include <cstdio> #include <algorithm> using namespace std; const int maxn = 10000 + 10; int a[maxn], b[maxn], c[maxn], n; double F(double x) { double ret = a[0]*x*x + b[0]*x + c[0]; for(int i = 1; i < n; i++) ret = max(ret, a[i]*x*x + b[i]*x + c[i]); return ret; } int main() { int T, i; scanf("%d", &T); while(T--) { scanf("%d", &n); for(i = 0; i < n; i++) scanf("%d%d%d", &a[i], &b[i], &c[i]); double L = 0.0, R = 1000.0, m1, m2; for(i = 0; i < 100; i++) { m1 = L + (R-L)/3; m2 = R - (R-L)/3; if(F(m1) < F(m2)) R = m2; else L = m1; } printf("%.4lf\n", F(L)); } return 0; }