HDU 1002 大数求和

题解

大数求和

代码

#include<iostream> 
#include<cstring> 
using namespace std;  
void sum(int lar,int sma,char lng[],char sht[],char add[])  
{  
    int p,q=0,i,j;  
    add[lar+1]='\0';  
    for(j=sma-1,i=lar-1;j>=0;j--,i--) 
        {  
            p=lng[i]-'0'+sht[j]-'0'+q;  
            if (p<10) {add[i+1]=p+'0';q=0;}  
            else {p=p%10; add[i+1]=p+'0';q=1;}  
        }  
    for(;i>=0;i--) 
        {  
            p=lng[i]-'0'+q;  
            if (p<10) {add[i+1]=p+'0';q=0;}  
            else {p=p%10; add[i+1]=p+'0';q=1;}  
        }  
    if (q==1) add[0]=1+'0';  
    else   
    {  
        for(i=0;i<lar+1;i++)  
            add[i]=add[i+1];  
    }  
}  
int main()  
{  
    int T,n=1,k;  
    cin>>T;  
    k=T;  
    while(T--) 
    {  
        char a[1001],b[1001],c[1002];  
        int A,B;  
        cin>>a>>b;  
        A=strlen(a);  
        B=strlen(b);  
        if (A>B) sum(A,B,a,b,c);  
        else sum(B,A,b,a,c);  
        if(n!=k)  
        {cout<<"Case "<<n<<":"<<endl;  
        cout<<a<<" + "<<b<<" = "<<c<<endl<<endl;}  
        else          
        {cout<<"Case "<<n<<":"<<endl;  
        cout<<a<<" + "<<b<<" = "<<c<<endl;}  
        n++;  
    }  
    return 0;  
}  

题目

Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is “Case #:”, # means the number of the test case. The second line is the an equation “A + B = Sum”, Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110