leetcode | Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

public class Solution {
    public static int compareVersion(String version1, String version2) {
        String[] v1 = version1.split("\\.");//.号要转义
        String[] v2 = version2.split("\\.");
        int i=0;
        for(i=0;i<v1.length&&i<v2.length;i++)
        {
            if(Integer.parseInt(v1[i])!=Integer.parseInt(v2[i]))
                return Integer.parseInt(v1[i])>Integer.parseInt(v2[i])?1:-1;
        }
        
        for(;i<v1.length;i++)
            if(Integer.parseInt(v1[i])!=0)
                return 1;
        for(;i<v2.length;i++)
            if(Integer.parseInt(v2[i])!=0)
                return -1;
        
        return 0;
    }
        
}