计算机学院大学生程序设计竞赛（2015’12）Study Words

Study Words

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 195    Accepted Submission(s): 66

Problem Description

Learning English is not easy, vocabulary troubles me a lot.
One day an idea came up to me: I download an article every day, choose the 10 most popular new words to study.
A word's popularity is calculated by the number of its occurrences.
Sometimes two or more words have the same occurrences, and then the word with a smaller lexicographic has a higher popularity.

 

Input

T in the first line is case number.
Each case has two parts.
<oldwords>
...
</oldwords>
<article>
...
</article>
Between <oldwords> and </oldwords> are some old words (no more than 10000) I have already learned, that is, I don't need to learn them any more.
Words between <oldwords> and </oldwords> contain letters ('a'~'z','A'~'Z') only, separated by blank characters (' ','\n' or '\t').
Between <article> and </article> is an article (contains fewer than 1000000 characters).
Only continuous letters ('a'~'z','A'~'Z') make up a word. Thus words like "don't" are regarded as two words "don" and "t”, that's OK.
Treat the uppercase as lowercase, so "Thanks" equals to "thanks". No words will be longer than 100.
As the article is downloaded from the internet, it may contain some Chinese words, which I don't need to study.

 

Output

For each case, output the top 10 new words I should study, one in a line.
If there are fewer than 10 new words, output all of them.
Output a blank line after each case.

 

Sample Input

   
   
   
   

    
    
    
    2
<oldwords>
how aRe you
</oldwords>
<article>
--How old are you?
--Twenty.
</article>
<oldwords>
google cn huluobo net i
</oldwords>
<article>
文章内容：
I love google,dropbox,firefox very much.
Everyday I open my computer , open firefox , and enjoy surfing on the inter-
net.
But these days it's strange that searching "huluobo" is unavail-
able.
What's wrong with "huluobo"?
</article>
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    old
twenty

firefox
open
s
able
and
but
computer
days
dropbox
enjoy
   
   
   
   

 

今天是2015年最后一个星期日，我用了好长好长好长时间做了这道题，测试答案不应该错，可是......... 好伤心、
不想再修改了。。。。就让它一直错吧！下面的是正确的答案哦！

#include<cstdio>
#include<cstring>
#include<map>
#include<string>
#include<algorithm>
using namespace std;
int T;
char s[100+10];
char r[100+10];
map<string,int>m;
struct dan
{
    char s[100+10];
    int num;
}d[1000000+10];
int sum;
int tot;
bool cmp(const dan&a,const dan&b)
{
    if(a.num==b.num) return strcmp(a.s,b.s)<0;
    return a.num>b.num;
}

//转小写
void F()
{
    for(int i=0;s[i];i++)
        if(s[i]>='A'&&s[i]<='Z')
            s[i]=s[i]-'A'+'a';
}
void work()
{
    int len=strlen(s);
    tot=0;
    for(int i=0;i<=len;i++)
    {
        if(s[i]>='a'&&s[i]<='z') r[tot++]=s[i];
        else
        {
            r[tot]='\0';
            if(strlen(r)>0) m[r]=-1;
            tot=0;
        }
    }
}
void work2()
{
    int len=strlen(s);
    tot=0;
    for(int i=0;i<=len;i++)
    {
        if(s[i]>='a'&&s[i]<='z') r[tot++]=s[i];
        else
        {
            r[tot]='\0';
            if(strlen(r)>0)
            {
                if(m[r]!=-1)
                {
                    if(m[r]==0) strcpy(d[sum++].s,r);
                    m[r]++;
                }
            }
            tot=0;
        }
    }
}
int main()
{
    scanf("%d",&T);
    while(T--)
    {
        int flag=0;
        m.clear();
        sum=0;
        while(1)
        {
            scanf("%s",s);
            if(strcmp(s,"<oldwords>")==0) {flag=1;continue;}
            if(strcmp(s,"</oldwords>")==0) {flag=2;continue;}
            if(strcmp(s,"<article>")==0) {flag=3;continue;}
            if(strcmp(s,"</article>")==0) break;
            if(flag==1)
            {
                F();
                work();
            }
            if(flag==3)
            {
                F();
                work2();
            }
        }
        for(int i=0;i<sum;i++) d[i].num=m[d[i].s];
        sort(d,d+sum,cmp);
        for(int i=0;i<min(10,sum);i++) printf("%s\n",d[i].s);
        printf("\n");
    }
    return 0;
}

@执念  "@☆但求“❤”安★下次我们做的一定会更好。。。。
为什么这次的题目是英文的。。。。QAQ...