2015创新工场涂鸦移动测试题-软件工程师

.将链表中的所有元素为奇数的节点移到元素为偶数节点的前面,并保证奇数之间顺序不变,偶数之间顺序不变。

 

示例:

交换前链表的顺序           交换后链表的顺序

4→5→3→1→2  ==>  5→3→1→4→2

1 ==> 1                (链表仅含一个元素)

2→1 ==>1→2 

       ==>       (链表为空)

 

C/C++:

链表节点定义为:

struct node {

struct node *next;

int value;

};

struct node *swap(struct node*list);

Java:

链表节点定义为:

classNode {

publicNode next;

public int value

}

Nodeswap(Node list)

 

注意点和要求如下:

1. swap函数要求对节点的指针/引用进行操作(不得创建任何新的链表节点)

2. 不得使用任何库函数/API,如需使用类似功能, 请自行实现

3.不得将链表转化为其他类型数据结构再进行交换,如数组等


#include <iostream>
#define Max 5 


using namespace std;

struct node {
	struct node *next;
	int value;
};


void CreatelistF(node *&L, int a[], int n)
{
	L = (node *)malloc(sizeof(node));
	L->value = n;
	L->next = NULL;
	for (int i = 0; i < n; i++)
	{
		node *s = (node *)malloc(sizeof(node));
		s->value = a[i];
		s->next = L->next;
		L->next = s;
	}
}

void Print(node *&L)
{
	node *temp;
	temp = L->next;
	while (temp != NULL)
	{
		printf("%d->", temp->value);
		temp = temp->next;
	}
	cout << endl;
}

void Reverse(node *&L)
{
	node *p = L->next, *q;
	L->next = NULL;
	while (p != NULL)
	{
		q = p->next;
		p->next = L->next;
		L->next = p;
		p = q;
	}
}

struct node *swap(struct node *list)
{
	if (list == NULL)
		return NULL;
	if (list->next == NULL)
		return list;
	node *p = list->next;
	node *OddHead = (node *)malloc(sizeof(node));
	node *EvenHead = (node *)malloc(sizeof(node));
	node *Odd = OddHead;
	node *Even = EvenHead;
	while (p)
	{
		if (p->value % 2 == 1)
		{
			Even->next = p;
			Even = p;
		}
		else
		{
			Odd->next = p;
			Odd = p;
		}
		p = p->next;
	}
	Odd->next = NULL;
	Even->next = OddHead->next;
	return EvenHead;
}
int main()
{
	int a[Max] = {4,5,3,1,2};
	node * L = (node *)malloc(sizeof(node));
	CreatelistF(L, a, Max);
	Reverse(L);
	cout << "the old list" << endl;
	Print(L);
	L = swap(L);
	cout << "the new list" << endl;
	Print(L);
	system("pause");
	return 0;
}


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