bzoj 2301: [HAOI2011]Problem b 【莫比乌斯反演】

链接:http://www.lydsy.com/JudgeOnline/problem.php?id=2301

题意:与hdu1695相似算是升级版吧。

分析:莫比乌斯。。

代码:

#include<algorithm>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<queue>
#include<cmath>
#include<stack>
#include<set>
#include<map>
#define INF 0x3f3f3f3f
#define Mn 50005
#define Mm 2000005
#define mod 1000000007
#define CLR(a,b) memset((a),(b),sizeof((a)))
#define CPY(a,b) memcpy ((a), (b), sizeof((a)))
#pragma comment(linker, "/STACK:102400000,102400000")
#define ul u<<1
#define ur (u<<1)|1
using namespace std;
typedef long long ll;
int read() {
    char c;
    int ans=0,f=1;c=getchar();
    while(c<'0'||c>'9') {if(c=='-')f=-1;c=getchar();}
    while(c>='0'&&c<='9') {ans=ans*10+c-'0';c=getchar();}
    return  ans*f;
}
int prime[Mn],tot=0,no[Mn];
int mo[Mn];int sum[Mn];
void mobius() {
    mo[1]=1;
    for(int i=2;i<=Mn;i++) {
        if(!no[i]) {
            prime[++tot]=i;
            mo[i]=-1;
        }
        for(int j=1;prime[j]*i<=Mn;j++) {
            no[prime[j]*i]=1;
            if(i%prime[j]==0) {
                mo[prime[j]*i]=0;
                break;
            }
            mo[prime[j]*i]=-mo[i];
        }
    }
}

ll solve(int a,int b) {
    ll re=0;
    if(a>b) swap(a,b);
    for(int i=1,last;i<=a;i=last+1) {
        last=min(a/(a/i),b/(b/i));
        re+=(ll)(sum[last]-sum[i-1])*(a/i)*(b/i);
    }
    return re;
}
int main() {
    mobius();sum[0]=0;
    for(int i=1;i<=Mn;i++)
        sum[i]=sum[i-1]+mo[i];
    int t=read();
    while(t--) {
        int a=read(),b=read(),c=read(),d=read(),k=read();
        ll ans=solve(b/k,d/k)-solve((a-1)/k,d/k)-solve(b/k,(c-1)/k)+solve((a-1)/k,(c-1)/k);
        printf("%lld\n",ans);
    }
    return 0;
}


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