Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
For example:
Given the following binary tree,
1 <--- / \ 2 3 <--- \ \ 5 4 <---
You should return [1, 3, 4]
.
【思路】广度遍历,从右到左,vector中只保存树每层最右边的一个节点。
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<int> rightSideView(TreeNode* root) { vector<int> result; if(NULL==root) return result; queue<pair<TreeNode*, int>> q; q.push(make_pair(root,0)); result.push_back(root->val); while(!q.empty()) { auto f = q.front(); q.pop(); if(f.first->right) { q.push(make_pair(f.first->right, f.second +1)); } if(f.first->left) { q.push(make_pair(f.first->left, f.second+1)); } if(!q.empty() && f.second != q.front().second) { result.push_back(q.front().first->val); } } return result; } };