POJ 3650 && HDU 2719 The Seven Percent Solution（水~）

Description
将一个字符串中七种特定的字符转化为另一种方式输出，转化方式如下:

Input
多组输入，每组用例占一行包括一个字符串，以#结束输入
Output
对于每组用例，输出转化后的字符串
Sample Input
Happy Joy Joy!
plain_vanilla
(**)
?
the 7% solution
#
Sample Output
Happy%20Joy%20Joy%21
plain_vanilla
%28%2a%2a%29
?
the%207%25%20solution
Solution
简单字符串处理
Code

#include<stdio.h>
#include<string.h>
char *table[7]={" ","!","$","%","(",")","*"},*table_plus[7]={"%20","%21","%24","%25","%28","%29","%2a"};
char s[100];
int main()
{
    int i;
    while(1)
    {
        gets(s);
        if(strcmp(s,"#")==0)//输入结束条件 
            return 0;
        for(char *p=s;*p;)
        {
            for(i=0;i<7;i++)
                if(strncmp(table[i],p,strlen(table[i]))==0)//找到匹配 
                {
                    printf("%s",table_plus[i]);
                    break;
                }
            if(i<7)//输出转化后的字符串 
                p+=strlen(table[i]);
            else//输出原字符 
                printf("%c",*p++);
        }
        printf("\n");
    }
}